The equation of the line that is perpendicular to y = -5/2 x + 1 and passing through (10, 3) will be y = 2/5 x + 1.
<h3>What is the linear system?</h3>
A linear system is one in which the parameter in the equation has a degree of one. It might have one, two, or even more variables.
The equation of the perpendicular line will be given as
y = mx + c
The given equation is y = -5/2 x + 1.
The slope of the line is -5/2.
Then the product of the slope of the perpendicular lines is a negative one.
-5/2 × m = - 1
m = 2/5
Then the equation will be
y = 2/5 x + c
Then the equation is passing through (10, 3). Then we have
3 = 2/5 × 10 + c
3 = 2 + c
c = 1
Then the equation is y = 2/5 x + 1.
More about the linear system link is given below.
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3x - 2y = 1
2x + 2y = 4
Add the second equation to the first
5x = 5
2x + 2y = 4
Divide the first equation by 5
x = 1
2x + 2y = 4
Subtract the first equation from the second
x = 1
x + 2y = 3
Subtract the first equation from the second again
x = 1
2y = 2
Divide the second equation by 2
x = 1
y = 1
<h3>
So, the solution is x = 1 and y = 1 {or: (1, 1)} </h3>
I don’t know what I’m solving for so I solved for h and with that it should be h=q/2+m/2
Explanation:
15h-m=13h+q
-13h -13h
———————-
2h-m=q
+m +m
———————-
2h=q+m
/2 /2 /2
———————-
H=q/2+m/2
Answer:
f(x) = -2|x| + 1
Step-by-step explanation:
The graph shifts one unit up the y axis since there's a value outside the absolute value which directly adds 1 to it.
