Answer:
Ix - 950°C I ≤ 250°C
Step-by-step explanation:
We are told that the temperature may vary from 700 degrees Celsius to 1200 degrees Celsius.
And that this temperature is x.
This means that the minimum value of x is 700°C while maximum of x is 1200 °C
Let's find the average of the two temperature limits given:
x_avg = (700 + 1200)/2 =
x_avg = 1900/2
x_avg = 950 °C
Now let's find the distance between the average and either maximum or minimum.
d_avg = (1200 - 700)/2
d_avg = 500/2
d_avg = 250°C.
Now absolute value equation will be in the form of;
Ix - x_avgI ≤ d_avg
Thus;
Ix - 950°C I ≤ 250°C
<span>
–1, 2.5, –6.25, 15.625, ...
r=-2.5
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</span>
<span>
8, 0.8, 0.08, 0.008, ...
r=0.1
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</span>
Yo sup??
This question can be solved by using the property
a²-b²=(a-b)(a+b)
Here a=A
b=C
plugging in the values
A^2-C^2=(A-C)(A+C)
Hope this helps
Answer:
A) 85x=5865
x=69 Width
B)2(57)+2x=286
114+2x=286
2x=172
x=86
Step-by-step explanation:
39=a 40=c 41=a 42=b 43=a 44=d 45=c 46=a 47=d. I hope this helped!
