Question

HELP ME..PLEASE!

Answer 1

Answer:

0.9375sec.

Step-by-step explanation:

Using the motion formula: V= u - gt

At Max. Height, V=0, taking t=32ft/sec^2

Thus: 0 = 30 - 32t

32t = 30

t=30/32

t= 0.9375sec

Therefore,

it will take 0.9375seconds which is less than 1 second to reach maximum height, then the ball starts descending. Just after 1 sec, ball is below its maximum height and in downward motion.