Answer:
0.9375sec.
Step-by-step explanation:
Using the motion formula: V= u - gt
At Max. Height, V=0, taking t=32ft/sec^2
Thus: 0 = 30 - 32t
32t = 30
t=30/32
t= 0.9375sec
Therefore,
it will take 0.9375seconds which is less than 1 second to reach maximum height, then the ball starts descending. Just after 1 sec, ball is below its maximum height and in downward motion.
