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kvv77 [185]
3 years ago
10

Which sum or difference is modeled by the algebra tiles?

Mathematics
1 answer:
Andrew [12]3 years ago
3 0

Answer:

C

Step-by-step explanation:

Blue is postive and Red is Negative so you would just write them down as seen and because x^2 is negative in the second equation there will be a subtraction sign to represent it.

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2x-4=3y+6 standard form
Mashcka [7]
That is in standard form.
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4 years ago
PLZZ HELP ME WITH THIS
Slav-nsk [51]
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How you would convert the repeating, nonterminating decimal to a fraction? Please EXPLAIN the process as you solve the problem,
zmey [24]
Okay, here we go.

With simpler decimals, this is a bit easier so I'll explain that first to make sure you get the basic idea. 

Let's say you had a decimal for .75 and wanted to create the fraction mathematically. To do this you would:

First divide the decimal by 1 so .75/1
Then multiply be a multiple of 10 that eliminates the decimal so in this case 100
so you now have 75/100
When you simplify that fraction by dividing by 25, you of course get 3/4

Now on to your more complicated question:

Let's assign a variable to your repeating decimal so:

x=.1515151515

Now, let's identify the repeating digits, here they are .15

Move one set of the repeating digits in front of the decimal  so now we get:

100x=15.1515151515

Now you have two equations, they are:

x=.1515151515
100x=15.1515151515

Combine the equations into one equation:

100x-x=15.1515151515-.1515151515
99x=15
15/99
simplify and you get 5/33





6 0
3 years ago
1. The midpoint of the segment joining points (a, b) and ( j, k) is: a. (j-a,k-b) b. ((j-a)/2,(k-b)/2) c. (j+a,k+b) d. ((j+a)/2,
harkovskaia [24]
1. The midpoint of the segment joining points (a, b) and ( j, k) is ((j+a)/2,(k+b)/2)

2. Let the coordinate of H be (a, b)
T(0, 4) = ((a + 0)/2, (b + 2)/2)
(a + 0)/2 = 0 => a + 0 = 0 => a = 0
(b + 2)/2 = 4 => b + 2 = (2 x 4) = 8 => b = 8 - 2 = 6
Therefore, the cordinate of H is (0, 6)

3. Point (-4, 3) lies in Quadrant II

4. Point (6, 0) lies on the x-axis

5. Any line with no slope is parallel to the y-axis

7. a is the value of the x-coordinate.
5a + 3 = 8
5a = 8 - 3 = 5
a = 5/5 = 1
a = 1

8. Equation of a circle is given by (x - a)^2 + (y - b)^2 = r^2; where (a, b) is the center and r is the radius.
For the given circle (x + 5)^2 + (y - 7)^2 = 36 => (x - (-5))^2 + (y - 7)^2 = 6^2 => a = -5 and b = 7.
Therefore, its center point is (-5, 7)

9. Equation of a circle is given by (x - a)^2 + (y - b)^2 = r^2; where (a, b) is the center and r is the radius.
For the given circle (x + 5)^2 + (y - 7)^2 = 36 => (x - (-5))^2 + (y - 7)^2 = 6^2 => r = 6.
Therefore, its radius is 6

10. If the equation of a circle is (x - 2)^2 + (y - 6)^2 = 4, the center is point (2, 6).
True

7 0
4 years ago
Read 2 more answers
What are the domain and range of this relation? {(3, -9), (11,21), (121,34), (34,1), (23,45)}
Simora [160]

Answer:

domain = ( 3, 11, 121, 34, 23)

range = ( 21, 34, 1, 23)

7 0
3 years ago
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