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yarga [219]
3 years ago
8

Factorize:

- p {2} = p - 1" alt="20 - 3p - p {2} = p - 1" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
yanalaym [24]3 years ago
7 0

Answer:

20 -3p -p^2 = p- 1

20 -3p -p = p^2 -1

20 -4p = p^2 -1

20 +1 = p^2 +4p

21 = p^2 +4p

p^2 +4p -21

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PLEASE HELP ASAP ILL GIVE 10 POINTS LOOK AT SCREENSHOT BELOW
maksim [4K]

Answer:

substitute x = 2

\frac{5 \times  {2}^{3} }{ {2}^{2} }

=  \frac{5 \times 8}{4}

=  \frac{40}{4}

= 10

6 0
3 years ago
Timmy and Sam ran in a marathon. Timmy ran at a constant speed of 5 miles per hour. Sam ran at a
Alinara [238K]

Given:

Speed of Timmy = 5 miles per hour

Speed of sam = 4 miles per hour and head start of 2 miles

To find:

Where Timmy and Sam will  meet.

Solution:

Let x be the number hours they ran in marathon and y be the total distance covered.

Speed of Timmy is 5 miles per hour. So, total distance covered by Timmy in x hours is

y=5x       ...(i)

Speed of sam is 4 miles per hour and head start of 2 miles. So, total distance covered by sam in x hours is

y=4x+2    ...(ii)

Now, equate (i) and (ii).

5x=4x+2

5x-4x=2

x=2

The value of x is 2. It means they will meet after 2 hours.

Put x=2 in (i).

y=5(2)

y=10

It means, they will meet at 10 miles.

6 0
3 years ago
F(x) = 5x - 3<br>f(5) =_____​
Vera_Pavlovna [14]

Answer:

22

Step-by-step explanation:

Evaluate!

5(5)-3

25-3

22

6 0
4 years ago
Explain why most sports are playing with spherical balls?
Olin [163]
Spherical balls have less friction compared to other type of balls, therefore, it could rolls in many direction
This will make the ball easier to control and made it more enjoyable for the audience to watch

hope this helps
8 0
3 years ago
Read 2 more answers
What is the solution to the trigonometric inequality 2sin(x)+3&gt;sin^2(x) over the interval 0&lt;=x&lt;=2pi radians?
devlian [24]

2 sin(x) + 3 > sin²(x)

can be rewritten as

sin²(x) - 2 sin(x) - 3 < 0

(sin(x) - 3) (sin(x) + 1) < 0

The left side is equal to zero when either

sin(x) - 3 = 0   or   sin(x) + 1 = 0

sin(x) = 3   or   sin(x) = -1

The first case can never happen for real x, since |sin(x)| ≤ 1. From the second case, we get one zero in the interval 0 ≤ x ≤ 2π at x = 3π/2.

Now, split up the solution domain into two intervals, and check the sign of the left side of the inequality at some point in the interval. If the inequality holds up, that interval will belong to the solution set for the inequality.

• From 0 ≤ x < 3π/2, take x = 0. Then

sin²(0) - 2 sin(0) - 3 = 0² - 0 - 3 < 0

is true.

• From 3π/2 < x ≤ 2π, take x = 2π. Then

sin²(2π) - 2 sin(2π) - 3 = 0² - 0 - 3 = -3 < 0

is also true.

This means both intervals 0 ≤ x < 3π/2 and 3π/2 < x ≤ 2π satisfy the inequality.

7 0
3 years ago
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