All categories

3 years ago

My question is

1 answer:

3 0

So 2 gallons every 5 minutes
2/5= .4
so .4 a minute
and you already have 5 gallons in so those need to be added
m=minutes
y=0.4m + 5 will be what you want to find out if you are looking to find out how much will be there in a certain time
for 50 minutes you will have
y=0.4(50) +5
20+5
25 gallons
HOWEVER, the equation has to be changed if you want to tell how long you have to wait for it to fill.
m=2.5(g-5)
m=minutes
g= gallons
you subtract 5 because they are already there
you multiply by 2.5 because it fills at a rate of 1 gallon every 2.5 minutes.
m=2.5(1500-5)
for the sake of it being easier i will do the -5 separately
2.5(1500 = 3750
2.5(-5= -12.5
3750-12.5
3737.5 minutes to fill the pool.
3720/60 = 62
17.5/60 = .292
62.292 hours to fill the pool.
p.s. you have a really slow hose.
Its good you didn't wait for it to fill, you would have died from lack of water before then if you just sat and waited.

You might be interested in

There are 278 houses in Hannah's neighborhood. She collected a total of $780 from her neighbors to donate for a local charity. H

ser-zykov [4K]

First, we need to find out how many houses that Hannah received money from. We can do this by dividing the total amount of money she received by the amount she received per house.

780 / 5 = 156

Hannah received money from 156 houses.
To find the amount of houses she did NOT collect money from, we just need to subtract the amount of houses that she DID receive money from away from the total amount of houses in her neighborhood.

278 - 156 = 122

Hannah did not collect money from 122 houses.
Hope this helped! =)

6 0

3 years ago

Read 2 more answers

Which inequality would result in the shaded solution on the unit circle to the right?

omeli [17]

<h3>Answer: Choice B</h3>

Explanation:

Cosine is positive in quadrants I and IV, but quadrant IV isn't shaded in so we can rule out choice A.

Sine is positive in quadrants I and II. So far it looks like choice B could work. In fact, it's the answer because sin(pi/6) = 1/2 and sin(5pi/6) = 1/2. So if 0 ≤ sin(x) < 1/2, then we'd shade the region between theta = 0 and theta = pi/6; as well as the region from theta = 5pi/6 to theta = pi.

Choice C is ruled out because tangent is positive in quadrants I and III, but quadrant III isn't shaded.

Choice D is ruled out for similar reasoning as choice A. Recall that $\sec(x) = \frac{1}{\cos(x)}$

5 0

2 years ago

Read 2 more answers

Methods of solving distance between two points

e-lub [12.9K]

The distance formula is an algebraic expression used to determine the distance between two points with the coordinates (x1, y1) and (x2, y2).

D=(x2−x1)2+(y2−y1)2−−−−−−−−−−−−−−−−−−√D=(x2−x1)2+(y2−y1)2

Example

Find the distance between (-1, 1) and (3, 4).

This problem is solved simply by plugging our x- and y-values into the distance formula:

D=(3−(−1))2+(4−1)2−−−−−−−−−−−−−−−−−−√=D=(3−(−1))2+(4−1)2=

=16+9−−−−−√=25−−√=5=16+9=25=5

Sometimes you need to find the point that is exactly between two other points. This middle point is called the "midpoint". By definition, a midpoint of a line segment is the point on that line segment that divides the segment in two congruent segments.

If the end points of a line segment is (x1, y1) and (x2, y2) then the midpoint of the line segment has the coordinates:

(x1+x22,y1+y22)(x1+x22,y1+y22)

3 0

3 years ago

Solve for x 11x+4<15 OR 12x−7>−25

never [62]

Isolate the x in both cases. What you do to one side, you do to the other.

11x + 4 < 15

Subtract 4 from both sides

11x + 4 (-4) < 15 (-4)

11x < 11

isolate the x, divide 11 from both sides

11x/11 < 11/11

x< 1

x < 1 is your answer for the first one

-------------------------------------------------------------------------------------------------------------------

Again, isolate the x.

12x - 7 > -25

Add 7 to both sides

12x - 7 (+7) > -25 (+7)

12x > -18

Isolate the x, divide 12 from both sides

12x/12 > -18/12

x > -1.5 is your answer for the second one.

-------------------------------------------------------------------------------------------------------------------

hope this helps

3 0

3 years ago

Read 2 more answers

Please walk me through how to do this so I can di the other questions

Naddik [55]

Answer:

Axis is a vertical line at x = 2

Vertex is (2, -1)

y-intercept is (0, 3)

Solutions are x = 1 and x = 3

Step-by-step explanation:

To draw the graph of the quadratic equation you must find at least 5 points lie on the graph by choose values of x and find their values of y

Let us do that

Use x = -1, 0, 1, 2, 3, 4, 5

∵ y = x² - 4x + 3

∵ x = -1

∴ y = (-1)² - 4(-1) + 3 = 1 + 4 + 3 = 8

→ Plot point (-1, 8)

∵ x = 0

∴ y = (0)² - 4(0) + 3 = 0 + 0 + 3 = 3

→ Plot point (0, 3)

∵ x = 1

∴ y = (1)² - 4(1) + 3 = 1 - 4 + 3 = 0

→ Plot point (1, 0)

∵ x = 2

∴ y = (2)² - 4(2) + 3 = 4 - 8 + 3 = -1

→ Plot point (2, -1)

∵ x = 3

∴ y = (3)² - 4(3) + 3 = 9 - 12 + 3 = 0

→ Plot point (3, 0)

∵ x = 4

∴ y = (4)² - 4(4) + 3 = 16 - 16 + 3 = 3

→ Plot point (4, 3)

∵ x = 5

∴ y = (5)² - 4(5) + 3 = 25 - 20 + 3 = 8

→ Plot point (5, 8)

→ Join all the points to form the parabola

From the graph

∵ The axis of symmetry is the vertical line passes through the vertex point

∵ x-coordinate of the vertex point is 2

∴ Axis is a vertical line at x = 2

∵ The coordinates of the vertex point of the parabola are (2, -1)

∴ Vertex is (2, -1)

∵ The parabola intersects the y-axis at point (0, 3)

∴ y-intercept is (0, 3)

∵ x² - 4x + 3 = 0

∵ The solutions of the equation are the values of x at y = 0

→ That means the intersection points of the parabola and the x-axis

∵ The parabola intersects the x-axis at points (1, 0) and (3, 0)

∴ Solutions are x = 1 and x = 3

3 0

3 years ago