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3 years ago

Which value from the set (5,7,9,11,13) make inequality w-4<8 true?

Mathematics

1 answer:

ira [324]3 years ago

8 0

Answer:

5,7,9,11

Step-by-step explanation:

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Need help with this find the value of x

dolphi86 [110]

Answer: x = √58
Decimal: 7.6157710 (Not Rounded)

Explanation: Using pythagorean theorem because it’s used for right triangle when mostly trying to find the hypotenuse.

3^2 + 7^ = c^2

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2 years ago

2x2 +5x+8<br> Given x 3-2, the expression<br> x+2.<br> is equivalent to

Masteriza [31]

Answer:

x=-1

Step-by-step explanation:

so 3-2 is 1 right so what humber + 2 is 1 well -1 becasue -1 + 1 is 0 and plus 2 would be 1 so its -1 (or x= -1). Hope this helped!

6 0

3 years ago

what is the distance between the line going through points (1, -5/4) and (1/3, -3/4) and the point (2, -3)?

Mamont248 [21]

Answer:

1.60078105936

Step-by-step explanation:

6 0

3 years ago

Mixed in a drawer are 44 blue socks, 88 white socks, and 44 gray socks. You pull out two socks, one at a time, without looki

MrRissso [65]

Answer:

The probability of getting 2 socks of the same color is 1/3.

Step-by-step explanation:

In the drawer,

Number of blue socks = 4

Number of white socks = 8

Number of gray socks = 4

Total number of socks = 4 + 8 + 4 = 16

Total ways to select 2 socks form 16 socks is

$^{16}C_2=\dfrac{16!}{2!(16-2)!}=120$

Total ways to select 2 socks of the same color is

T = Possible ways of (2 blue + 2 white +2 gray) socks

= $^{4}C_2+^{8}C_2+^{4}C_2$

= $6+28+6$

= $40$

The probability of getting 2 socks of the same color is

$Probability=\dfrac{\text{Total ways to select 2 socks of the same color}}{\text{Total ways to select 2 socks form 16 socks}}$

$Probability=\dfrac{40}{120}$

$Probability=\dfrac{1}{3}$

Therefore, the probability of getting 2 socks of the same color is 1/3.

3 0

3 years ago

A firm offers routine physical examinations as part of a health service program for its employees. The exams showed that 8% of t

Alexxandr [17]

Answer: A. 0.20

Step-by-step explanation:

Let A be the event of employees needed corrective shoes and B be the event that they needed major dental work .

We are given that : $P(A)=0.08\ ;\ P(B)=0.15\ ;\ P(A\cap B)=0.03$

We know that $P(A\cup B)=P(A)+P(B)-P(A\cap B)$

Then, $P(A\cup B)=0.08+0.15-0.03= 0.20$

Hence, the probability that an employee selected at random will need either corrective shoes or major dental work : $P(A\cup B)= 0.20$

hence, the correct option is (A).

6 0

4 years ago