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2 years ago

A line segment has end points at (-3, -5) and (4, 1). What is it’s length?

Mathematics

1 answer:

Whitepunk [10]2 years ago

6 0

Answer:

You need to add the number of blocks or lines are betweenhem.

Step-by-step explanation:

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Fine the exact distance between the line 6x-y=-3 and the point (6,2). Show your work. Explain your answer.

AVprozaik [17]

Answer:

$\sqrt{37}$ units

Step-by-step explanation:

If we draw a perpendicular from point (6,2) on the line 6x - y = - 3, then we have to find the length of the perpendicular.

We know the formula of length of perpendicular from a point $(x_{1}, y_{1} )$ to the straight line ax + by + c = 0 is given by

$\frac{|ax_{1} + by_{1} +c |}{\sqrt{a^{2}+b^{2}}}$

Therefore, in our case the perpendicular distance is

$\frac{|6(6)-2+3|}{\sqrt{6^{2} +(-1)^{2} } } = \frac{37}{\sqrt{37} } = \sqrt{37}$ units. (Answer)

6 0

3 years ago

200,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000+1

Masja [62]

Answer:

200,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,001

Step-by-step explanation:

6 0

2 years ago

3. A rocket is launched vertically from the ground with an initial velocity of 64 ft / sec . ( a ) Write a quadratic function h

lys-0071 [83]

Answer:

See below.

Step-by-step explanation:

The rocket's flight is controlled by its initial velocity and the acceleration due to gravity.

The equation of motion is h(t) = ut + 1.2 g t^2 where u = initial velocity, g = acceleration due to gravity ( = - 32 ft s^-2) and t = the time.

(a) h(t) = 64t - 1/2*32 t^2

h(t) = 64t - 16t^2.

(b) The graph will be a parabola which opens downwards with a maximum at the point (2, 64) and x-intercepts at (0, 0) and (4, 0).

The y-axis is the height of the rocket and the x-axis gives the time.

Maximum height = 64 feet, Time to maximum height = 2 seconds, and time in the air = 4 seconds.

6 0

3 years ago

Read 2 more answers

Find the value of x.

krok68 [10]

Answer:

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%20%5Cpi%20%20x%5E%7B2%7D%20" id="TexFormula1" title=" \pi x^{2} " alt=" \pi x^{2} " align="

ANEK [815]

The formule is about area of a circle.

$\pi x^{2} = a$

We need to solve the equation for x. Where x is the radius of the circle.

In order to solve it for x, we need isolate it for x on left side.

So, first we need to get rid pi from left side.

On dividing both sides by pi, we get

$\frac{\pi x^2}\pi}=\frac{a}{\pi}$

$x^2=\frac{a}{\pi}$

Taking square root on both sides, we get

$\sqrt{x^2}=\sqrt{\frac{a}{\pi}}$

$x=\sqrt{\frac{a}{\pi}}$

4 0

3 years ago