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MA_775_DIABLO [31]
3 years ago
14

Help please Working on stuff for a class need an answer.

Mathematics
1 answer:
creativ13 [48]3 years ago
4 0

Answer:

2a^3(\sqrt[4]{9b^3} )

Step-by-step explanation:

Given:

\sqrt[4]{144a^{12}b^3}

144 as a product of its prime factors  is 2^4\times 3^2

Now, a^{12} can be written as (a^3)^4     (\because (a^m)^n=a^{m\times n})

We know that, \sqrt[4]{a^4} =a

Hence, the given expression becomes,

\sqrt[4]{2^4\times 3^2\times (a^3)^4\times b^3} \\=2a^3(\sqrt[4]{3^2\times b^3}\\ =2a^3(\sqrt[4]{9b^3})

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Just subtract 8-3 and 8-4 and you'll get 5.4

Hope it helps!

*************************************************

Brainliest please if you found my answer helpful! :)

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