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Radda [10]
3 years ago
13

Whay 3 tims 99 Pls help confused thanks

Mathematics
2 answers:
timurjin [86]3 years ago
6 0
3 times 99 is 297...
ryzh [129]3 years ago
6 0
I'm not sure I understand what the problem is. 3x100-3=297
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HELP PLSSSSSSSSSSSSSSS ASAP
makvit [3.9K]

Answer:

26

Step-by-step explanation:

Sydney = x

Devaughn = 2x

x + 2x = 78

3x = 78

x = 78 / 3

x = 26

Hope that helps!

6 0
2 years ago
Read 2 more answers
What is <br> (x - 3)(x +9)
wel

Answer:

x^2 +6x-27

Step-by-step explanation:

7 0
3 years ago
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BRAINTEASER MATH 1. Multiple me by 20 and the awnser is 10 what am i________ 2.I am a prime number over 70 and less then 80 what
IgorC [24]
1) 0.5 , 2)<span>71 or 73 or 79  , 3) well i would say 999</span>
8 0
3 years ago
What is the result when x^3+ 7x^2+ 9x - 8 is divided by x+ 2?
Ahat [919]

Answer:

\frac{x^3+7x^2+9x-8}{x+2}=x^2+5x-1+\frac{-6}{x+2}

So the quotient is 1x^2+5x+-1 and the remainder is -6.

Step-by-step explanation:

We could do this by synthetic division since the denominator is a linear factor in the form x-c.

Since we are dividing by x+2=x-(-2), this is our setup for the synthetic division:

-2 |     1    7    9    -8

   |         -2   -10     2

   ______________

          1   5    -1       -6

So the quotient is 1x^2+5x+-1 and the remainder is -6.

So \frac{x^3+7x^2+9x-8}{x+2}=x^2+5x-1+\frac{-6}{x+2}.

We can also do long division.

                 x^2+5x-1

               ____________________

        x+2| x^3+7x^2+9x-8

              -(x^3+2x^2)

              -------------------

                       5x^2+9x-8

                    -( 5x^2+10x)

                      --------------------

                                 -x-8

                               -(-x-2)

                                --------------

                                      -6

So we see here we get the same quotient, x^2+5x-1. and the same remainder, -6.

Now let's check our result that:

\frac{x^3+7x^2+9x-8}{x+2}=x^2+5x-1+\frac{-6}{x+2}.

So I'm going to rewrite the right hand side as a single fraction:

\frac{x^3+7x^2+9x-8}{x+2}=\frac{(x+2)(x^2+5x-1)}{x+2}+\frac{-6}{x+2}.

\frac{x^3+7x^2+9x-8}{x+2}=\frac{(x+2)(x^2+5x-1)-6}{x+2}

Now let's focus on multiplying (x+2)(x^2+5x-1).

We are going to multiply the first term of the first ( ) to every term in the second ( ).

We are also going to multiply the second term of the first ( ) to every term in the second ( ).

x(x^2)=x^3

x(5x)=5x^2

x(-1)=-x

2(x^2)=2x^2

2(5x)=10x

2(-1)=-2

---------------------------Combine like terms:

x^3+(5x^2+2x^2)+(-x+10x)+-2

x^3+7x^2+9x-2

So let's go back where we were in our check of \frac{x^3+7x^2+9x-8}{x+2}=x^2+5x-1+\frac{-6}{x+2}:

\frac{x^3+7x^2+9x-8}{x+2}=\frac{(x+2)(x^2+5x-1)-6}{x+2}

\frac{x^3+7x^2+9x-8}{x+2}=\frac{x^3+7x^2+9x-2-6}{x+2}

\frac{x^3+7x^2+9x-8}{x+2}=\frac{x^3+7x^2+9x-8}{x+2}

We have the exact same thing on both sides so we did good.

4 0
3 years ago
Read 2 more answers
-5x+4y=3<br> x=2y-15 please help me
defon
Y = 5
That is the answer to your question
7 0
2 years ago
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