750 / 10 = 75 bushels per acre
75 * 14 = 1,050 bushels of corn
Answer:
<h3>
Assuming A, B, and C are collinear and B is between A and C then x = -2
2</h3>
Step-by-step explanation:
Assuming A, B, and C are collinear and B is beetween A and C
AB + BC = AC
48 + 2x + 139 = x + 165
2x + 187 = x + 165
x = -22
Answer: 25 < P < 36
15/4 < w < 26/4
35/4 < L < 46/4
<u>Step-by-step explanation:</u>
Perimeter is BETWEEN 25 and 36
25 < P < 36
Graph: O--------------O
25 36
Perimeter = 2L + 2w ; substitute L = w + 5
25 < 2(w + 5) + 2w < 36
25 < 2w + 10 + 2w < 36
25 < 4w + 10 < 36
15 < 4w < 26
< w < 
< w < 
Graph: O------------------------O
Perimeter = 2L + 2w ; L = w + 5 --> w = L - 5
25 < 2L + 2(L - 5) < 36
25 < 2L + 2L - 10 < 36
25 < 4L - 10 < 36
35 < 4L < 46
< L < 
< L < 
Graph: O------------------------O
Note: Make sure you use OPEN dots when graphing.
Because LP and NP are the same measure, that means that MP is a bisector. It bisects side LN and it also bisects angle LMN. Where MP meets LN creates right angles. What we have then thus far is that angle LMP is congruent to angle NMP and that angle LPM is congruent to angle NPM and of course MP is congruent to itself by the reflexive property. Therefore, triangle LPM is congruent to triangle NMP and side LM is congruent to side NM by CPCTC. Side LM measures 11.
Answer:
c. x21 + x22 + x23 less or equal than 2800 y2
Step-by-step explanation:
The plant has a maximum capacity of 2800 then the sum of all these operations must be equal to or less than 2800. The site of the plant has capacity constraint which needs to be determine through equation. The total capacity for the plant 2 is only 2800 the operation has to be distributed with keeping in mind the capacity limit.
