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Alona [7]
3 years ago
14

Find the absolute value. The absolute value of 5 is​

Mathematics
2 answers:
g100num [7]3 years ago
8 0

Answer:

5

Step-by-step explanation:

The reason it is 5, not -5, is because the absolute value can never be a negative number! Only positive. Remember that

Cheers! Hope you understand

Luba_88 [7]3 years ago
4 0

Answer:

5

Step-by-step explanation:

you need to look at how far it is from a m=number line to find the absolute value

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Find the mode for the price of movie tickets at various theaters. $5, $4, $7, $9, $5, $8, $5, $3, $6, $5, $7, $4, $5, $4
kupik [55]

5 is the most occurring number

Step-by-step explanation:

3 0
3 years ago
Combine the like terms to create an equivalent expression:
Nesterboy [21]

Answer:

-2z+8

Step-by-step explanation:

3z+2+(-5x)+6\\\\=3z+2-5x+6\\\\=(3z-5z)+(2+6)\\\\=(-2z)+(8)\\\\=-2z+8

6 0
3 years ago
What is the value of y?
RUDIKE [14]

Answer:

C. 55

Step-by-step explanation:

Since all angles in a triangle add up to 180°, we have:

40 + y + y + 30 = 180

2y + 70 = 180

2y = 110

y = 55

7 0
3 years ago
Read 2 more answers
A linear equation has more than one intercept. what can you conclude about the graph of the equation?
DanielleElmas [232]
A linear equation of the form :

y = mx+b

can have at the most ONE x-intercept and at the most ONE y-intercept

I can conclude that this linear equation DOESN'T pass through the origin (O) and that it intercepts the x-axis as well as the y-axis

5 0
3 years ago
{4x-2y+5z=6 <br> {3x+3y+8z=4 <br> {x-5y-3z=5
lesya692 [45]

There are three possible outcomes that you may encounter when working with these system of equations:


  •    one solution
  •    no solution
  •    infinite solutions

We are going to try and find values of x, y, and z that will satisfy all three equations at the same time. The following are the equations:

  1. 4x-2y+5z = 6
  2. 3x+3y+8z = 4
  3. x-5y-3z = 5

We are going to use elimination(or addition) method

Step 1: Choose to eliminate any one of the variables from any pair of equations.

In this case it looks like if we multiply the third equation by 4 and  subtracting it from equation 1, it will be fairly simple to eliminate the x term from the first and third equation.

So multiplying Left Hand Side(L.H.S) and Right Hand Side(R.H.S) of 3rd equation with 4 gives us a new equation 4.:

4. 4x-20y-12z = 20      

Subtracting eq. 4 from Eq. 1:

(L.HS) : 4x-2y+5z-(4x-20y-12z) = 18y+17z

(R.H.S) : 20 - 6 = 14

5. 18y+17z=14

Step 2:  Eliminate the SAME variable chosen in step 2 from any other pair of equations, creating a system of two equations and 2 unknowns.

Similarly if we multiply 3rd equation with 3 and then subtract it from eq. 2 we get:

(L.HS) : 3x+3y+8z-(3x-15y-9z) = 18y+17z

(R.H.S) : 4 - 15 = -11

6. 18y+17z = -11

Step 3:  Solve the remaining system of equations 6 and 5 found in step 2 and 1.

Now if we try to solve equations 5 and 6 for the variables y and z. Subtracting eq 6 from eq. 5 we get:

(L.HS) : 18y+17z-(18y+17z) = 0

(R.HS) : 14-(-11) = 25

0 = 25

which is false, hence no solution exists



3 0
3 years ago
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