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3 years ago

13

A fencing company charges $22 per foot to install a wood fence. How much will it cost to install a wood fence around a rectangul

ar pool area that is 20 feet wide and 38 feet long?

1 answer:

borishaifa [10]3 years ago

4 0

20+20+38+38=116

116×22 = 2552

It will cost $2,552 to install the wood fence.

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Levart [38]

The answer would be D. 32

Why? The triangle in the problem is an isosceles triangle. That means the two legs of the triangle are equal and the angle opposite to the equal legs are also equal.

Therefore, angle C is also 74°.

The sum of the interior angles of a triangle is equal to 180°.
Thus,
180° = ∡A + ∡B + ∡C
180° = 74° + ∡B + 74°
180° = 148° + ∡B
∡B = 180° - 148°
∡B = 32°

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3 years ago

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3 years ago

A ball has a volume of 4 cubic inches (in3). Use the fact that 1 inch is equal to 2.54 cm to convert this volume to cubic centim

Marina86 [1]

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Step-by-step explanation:

We have,

Volume of a ball is 4 cubic inches or $4\ \text{inch}^3$ .

We know that, 1 inch = 2.54 cm

It is required to convert this volume to cubic centimetre or $\text{cm}^3$ .

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So, the volume of the ball is 65.548 cm³.

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balu736 [363]

Answer:

$\lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=0$

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Assuming the correct expression is to find the following limit:

$\lim_{x \to 1}\frac{x^2-1}{sin(x-2)}$

Use the property the limit of the quotient is the quotient of the limits:

$\lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=\frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}$

Evaluate the numerator:

$\frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}=\frac{1^2-1}{\lim_{x \to1}sin(x-2)}=\frac{0}{\lim_{x \to 1}sin(x-2}$

Evaluate the denominator:

Since $\lim_{x \to1}sin(x-2)\neq 0$

$\frac{0}{\lim_{x \to1}sin(x-2)}=0$

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Answer:

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