Quadrilateral ABCD is a rectangle.
1 answer:
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Answer:
Vertex (-2.5,-300)
Step-by-step explanation:
We are given with h(t)=-16 t^2 +80 t. We are asked to find the vertex.
X-coordinate of vertex =
Where 'a' is coefficient of term
'b' is coefficient of 't' term.
From given function, a= -16
b=80
So,
x-coordinate of vertex =
=-2.5
y-coordinate of vertex =
Simplify it,
=-100 -200
= -300
So, vertex is at (-2.5, -300).
Answer: y = -4x - 4
Step-by-step explanation:
Point slope form: y - y1 = m(x - x1)
Plug in y1 and x1, and m. M is the slope, x1 and y1 are the values for a coordinate. You don't need to plug anything in for y or x, just y1 and x1.
First, find the slope. To find the slope, use this "formula" :
Find two coordinate points. Let's use (-2,4) and (0,-4). Based on this, we know that y1 is 4, y2 is -4, x1 is -2, and x2 is 0. Plug these into the formula:
Then, pick any point to plug into the equation. Let's use (0,-4)
Finally, plug everything into the equation:
y - - 4 = -4(x - 0)
y + 4 = -4x
y = -4x - 4