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mojhsa [17]
4 years ago
9

HELP ME PLEASE!!!!

Mathematics
1 answer:
navik [9.2K]4 years ago
5 0
24=4\cdot6\\96=16\cdot6\\\\2\sqrt6-4\sqrt{24}+\sqrt{96}=2\sqrt6-4\sqrt{4\cdot6}+\sqrt{16\cdot6}\\\\=2\sqrt6-4\cdot\sqrt4\cdot\sqrt6+\sqrt{16}\cdot\sqrt6=2\sqrt6-4\cdot2\cdot\sqrt6+4\cdot\sqrt6\\\\=2\sqrt6-8\sqrt6+4\sqrt6=(2-8+4)\sqrt6=-2\sqrt6\\\\\text{Answer:}\ -2\sqrt6\\\\\text{Used:}\ \sqrt{a\cdot b}=\sqrt{a}\cdot\sqrt{b}
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A sensor output was acquired for 32 seconds at a rate of 200 Hz and spectral analysis was performed using FFT. If the data set w
VashaNatasha [74]

Complete Question

A sensor output was acquired for 32 seconds at a rate of 200 Hz and spectral analysis was performed using FFT. If the data set was split into 5 segments (each 6.4 seconds long), what is the resulting:

a)F minimum

b) F maximum

c) Frequency resolution

Answer:

a) Fmax=100Hz

b) Fmin=0Hz

c) F_r=0.0313

Step-by-step explanation:

From the question we are told that:

Time t=32sec

FrequencyF=200Hz

Segments \mu=5

Generally the equation for Frequency Range is mathematically given by

Fmax=\frac{F}{2}

Fmax=100Hz

Therefore

a) Fmax=100Hz

b) Fmin=0Hz

c)

Generally the equation for Frequency Resolution is mathematically given by

F_r=\frac{F}{N}

Where

N=The Total dat points

N=Sampling Frequency *Time

N=200*32

N=6400

Therefore

F_r=\frac{200}{6400}

F_r=0.0313

6 0
3 years ago
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Aleksandr [31]

Answer:

106 and 93

Step-by-step explanation:

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4 0
3 years ago
Using standard algorithm what does 82 times 18 equal
VashaNatasha [74]
82 times 18 would add up to 1,476. Hope this helped. 
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Gnoma [55]

Answer:

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Step-by-step explanation:

Please see attached picture for full solution.

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3 years ago
PLEASE HELP!!!!
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C. The area is increased by an area of 25

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3 years ago
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