Probably 2 because It doesn't matter how many beads are in the bag and for 33.34% you would probably draw 2 beads before on the third draw getting a red one and 30% is close to 33.34% then I would you would probably draw 2 beads before drawing a red one.
1) The sum of the two numbers is even either the two numbers are even or the two numbers are odd.
2) The probability that the two numbers are even is the product of the probabilities for each event:
- Probability that the first number is even: 10 / 20 = 0.5
- Probability that the second number is even: 10 / 20 = 0.5
- Probability that the two numbers are even: 0.5*0.5 = 0.25
3) The probability that the two numbers are odd is the product of the probabilities for each event:
- Probability that the first number is 0dd: 10/20 = 0.5
- Probability that the second number is odd: 10/20 = 0.5
- Probability that both numbers is odd = 0.5*0.5 = 0.25
4) Probability tha the sum is eve: 0.25 + 0.25 = 0.5
Answer: 0.5.
And it is reasonable, half of times the sum is even and half the sum is odd.
Y-1=10
+1. +1
So y = 11
Hope that helps
Answer:
I remember it was Triangular prism or something
Step-by-step explanation:
2 triangles on top
and the sides with rectangle.
