The price of this wrapping paper per inch is equal to $1,198.08.
<u>Given the following data:</u>
- Cost of wrapping paper = $12.48.
- Length of wrapping paper = 8 foot.
To determine the price of this wrapping paper per inch:
<h3>
How to solve the problem.</h3>
In this exercise, you're required to solve for the cost of an 8-foot roll of wrapping paper that costs $12.48. Thus, we would convert the length of this wrapping paper in foot to inch and then multiply by $12.48.
<u>Conversion:</u>
1 foot = 12 inch
8 foot = X inch
Cross-multiplying, we have:
X = 96 inch
For price per inch:
Price = $1,198.08
Read more on word problems here: brainly.com/question/13170908
Answer:
see explanation
Step-by-step explanation:
x = r cosΘ
y = r sinΘ
with r = 54 and Θ = 69°, thus
x = 54cos69° ≈ 19.4
y = 54sin69° ≈ 50.4
Thus (54, 69° ) as an ordered pair
= ![\left[\begin{array}{ccc}19.4\\50.4\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D19.4%5C%5C50.4%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Answer:
19/20
Step-by-step explanation:
write all numerators above the common denominator 20
14+5/20
19/20
Answer:
If you mean the flag it is just to mark the question if you have trouble with it so you can remember to go back and check
Step-by-step explanation:
Answer:
0.84 square in
Step-by-step explanation:
Since the capacity of the cable is proportional to its cross-sectional area. If a cable that is 0.3 sq in can hold 2500 lb then per square inch it can hold
2500 / 0.3 = 8333.33 lb/in
To old 7000 lb it the cross-sectional area would need to be
7000 / 8333.33 = 0.84 square in
