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Leona [35]
4 years ago
11

Which is an example of dependent events? rolling a die three times/ spinning a spinner two times/ choosing two numbered slips fr

om a hat with replacement/ choosing two socks from a drawer of black and white socks without replacement? need answer fast plz guys
Mathematics
2 answers:
elena-s [515]4 years ago
6 0
The fourth event is dependent.  Not replacing draws changes the probability of drawing a certain number or thing.

Rus_ich [418]4 years ago
4 0

Answer:

Two or more events are said to be Dependent if occurence of one is dependent on the occurence of other.

For example: In a bag there are three different colored balls each being 5 in number.Drawing three balls one by one without replacement from the bag is a dependent event.

Out of the given options following are example of dependent events.

1. Rolling a die three times

 When you roll a die three times , each roll is independent of other.So, it is an example of Independent event.

2. Spinning a spinner two times

When you Spin a Spinner two times , each roll is independent of other.So, it is an example of Independent event.

3.Choosing two numbered slips from a hat with replacement

As you are replacing the numbered slips from the hat,it will not alter the total possible Outcome.So, it is an example of Independent event.

4. Choosing two socks from a drawer of black and white socks without replacement

Drawing Socks from the drawer and then not replacing the socks after each event will affect the total Possible outcome.So,each draw will become dependent on another.

  it is an example of Dependent event.

Option 4: Choosing two socks from a drawer of black and white socks without replacement , is an example of dependent event.

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Answer: $ 8.97

Step-by-step explanation:

Game =$9.78

toy=$ 6.34

sandwich =$4.91

Total amount  spent=$9.78+$6.34+$4.91=>  $21.03

Total amount=$30

left amount=total amount- amount spent

=   $30-&21.03

 =$8.97

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Graph please help x and y values
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(-5, 1)

Step-by-step explanation:

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A=120mins <br> B=20mins<br> C=40mins<br> D=80mins
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8 0
3 years ago
Read 2 more answers
Suppose the mean percentage in Algebra 2B is 70% and the standard deviation is 8% What percentage of students receive between a
LUCKY_DIMON [66]

Answer:

49.87

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Suppose the mean percentage in Algebra 2B is 70% and the standard deviation is 8%.

This means that \mu = 70, \sigma = 8

What percentage of students receive between a 70% and 94%

The proportion is the p-value of Z when X = 94 subtracted by the p-value of Z when X = 70. So

X = 94

Z = \frac{X - \mu}{\sigma}

Z = \frac{94 - 70}{8}

Z = 3

Z = 3 has a p-value of 0.9987.

X = 70

Z = \frac{X - \mu}{\sigma}

Z = \frac{70 - 70}{8}

Z = 0

Z = 0 has a p-value of 0.5.

0.9987 - 0.5 = 0.4987.

0.4987*100% = 49.87%.

So the percentage is 49.87%, and the answer, without the percent sign, is 49.87.

8 0
3 years ago
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