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3 years ago

A scammer scanned 63 photos in 9 minute if it scans photos at a constant rate it can scan___ photos in 21 minutes (20 points)

Mathematics

1 answer:

Nikitich [7]3 years ago

4 0

The answer to this is 147. Just divided 9 by 63 :)

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What happens to the value of the expression \dfrac5x+5 x 5 +5start fraction, 5, divided by, x, end fraction, plus, 5 as xxx de

aleksandr82 [10.1K]

Answer:

It increases

Step-by-step explanation:

(5/x) + 5

As x decreases, 5/x increases. So the expression increases.

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3 years ago

Read 2 more answers

Which of the following linear equations represents the data chart?

BlackZzzverrR [31]

Answer: y = -x + 7

Step-by-step explanation:

The slope is $\frac{5-6}{2-1}=-1$ , so we know the equation is of the form $y=-x+b$ .

Substituting in the coordinates (1,6) to find b,

$6=-1+b\\\\b=7$

Thus, the equation is y = -x + 7

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2 years ago

The task is in the attachment, thank you

Novosadov [1.4K]

Answer:

m=0

Step-by-step explanation:

if x=1/2 then

m(1/2)² +2(1/2)-1=0

m/4+1-1=0

m/4=0

m=0

4 0

3 years ago

A lot for sale is shaped like a trapezoid. The bases of the trapezoid represent the widths of the front and back yards. The widt

Rasek [7]

Answer

Front yard is 20 square root 5 back yard and height is 40 square root 5

Step-by-step explanation:

1. set up A=1/2 H(b1+b2)

2. 6000=1/2 2x (2x+x)

3. 12000=6x^2

4.2000 = x^2

5. x=20 square root 5

8 0

3 years ago

B: Alex is 12 years older than George.

UkoKoshka [18]

Answer:

The ratio of George age to Carl's age is 1:12.

Step-by-step explanation:

Let the age of George be 'g'.

Let the age of Alex be 'a'.

Also Let the age of Carl be 'c'.

Given:

The sum of their ages is 68.

So equation can be framed as;

$g+a+c=68 \ \ \ \ equation 1$

Also Given:

Alex is 12 years older than George.

So equation can be framed as;

$a =g+12 \ \ \ \ equation \ 2$

Now Given:

Carl is three times older than Alex.

$c=3a$

But $a =g+12$

So we get;

$c = 3(g+12) \\\\c= 3g+36 \ \ \ \ equation \ 3$

Now Substituting equation 2 and equation 3 in equation 1 we get;

$g+a+c=68\\\\g+g+12+3g+36=68\\\\5g+48=68$

Subtracting both side by 48 using subtraction property of equality we get;

$5g+48-48=68-48\\\\5g=20$

Now Dividing both side by 5 using Division property of equality we get;

$\frac{5g}{5}=\frac{20}{5}\\\\g =4$

Hence George age $g = 4 \ years$

Now Alex age $a=g+12 = 4+12 =16\ years$

Also Carl's age $c=3g+36=3\times 4+36 =12+36 =48\ years$

Now we need to find the ratio of George age to Carl's age.

$\frac{g}{c}=\frac{4}{48} = \frac{1}{12}$

Hence the ratio of George age to Carl's age is 1:12.

3 0

3 years ago