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3 years ago

What is the expanded form for 102,200

Mathematics

2 answers:

Vedmedyk [2.9K]3 years ago

7 0

Answer:

100,00+2,000+200

Step-by-step explanation:

solmaris [256]3 years ago

4 0

Answer: 100,000 + 2000 + 200

Hope this helps!

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3 years ago

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Elena’s aunt bought her a $150 savings bond when she was born. When Elena is 20 years old, the bond will have earned interest an

Ghella [55]

Answer:

307.5$

Step-by-step explanation:

150$. 105% of it added.

Since 105% is 1.05, multiply the percentage by the cost to get the money added.

150*1.05=157.5

Then ADD it to the price/savings.

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Hey can someone help me with this .

algol [13]

The right awnser is A

3 0

3 years ago

EXPAND:

Sladkaya [172]

Answer:

$\displaystyle A) 5\log( {x}^{} ) + 2 \log( {y}^{} )$

Step-by-step explanation:

we would like to expand the following logarithmic expression:

$\displaystyle \log( {x}^{5} {y}^{2} )$

remember the multiplication logarithmic indentity given by:

$\displaystyle \rm \log( \alpha \times \beta ) \iff \log( \alpha ) + \log( \beta )$

so our given expression should be

$\displaystyle \log( {x}^{5} ) + \log( {y}^{2} )$

by exponent logarithmic property we acquire:

$\displaystyle 5\log( {x}^{} ) + 2 \log( {y}^{} )$

hence, our answer is A

5 0

3 years ago

what is the probability of seeing a sample mean for 21 observations less or equal to the sample mean that we observed

kramer

Answer:

$P(x \le 21) = 0.69146$

Step-by-step explanation:

The missing parameters are:

$n = 64$ --- population

$\mu = 20$ --- population mean

$\sigma = 16$ -- population standard deviation

Required

$P(x \le 21)$

First, calculate the sample standard deviation

$\sigma_x = \frac{\sigma}{\sqrt n}$

$\sigma_x = \frac{16}{\sqrt {64}}$

$\sigma_x = \frac{16}{8}$

$\sigma_x = 2$

Next, calculate the sample mean $\bar_x$

$\bar x = \mu$

So:

$\bar x = 20$

So, we have:

$\sigma_x = 2$

$\bar x = 20$

$x = 21$

Calculate the z score

$x = \frac{x - \mu}{\sigma}$

$x = \frac{21 - 20}{2}$

$x = \frac{1}{2}$

$x = 0.50$

So, we have:

$P(x \le 21) = P(z \le 0.50)$

From the z table

$P(z \le 0.50) = 0.69146$

So:

$P(x \le 21) = 0.69146$

4 0

3 years ago