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bulgar [2K]
2 years ago
5

Thomas is running for class president. e can have a campaign buttons made for a one-time fee of $23.60,plus $0.50 for each butto

n. what is the maximum nmber of buttons tomas can have made his campaign buget only has $257.00 left in it.
A) 116 buttons
B) 514 buttons
C) 467 buttons
D) 466 buttons
Mathematics
2 answers:
Troyanec [42]2 years ago
4 0
Write and solve this inequality:

$23.60 + ($0.50)x ≤ $257

                           
Then ($0.50)x ≤ $233.40
             
                  $233.40
Then x ≤ --------------  , or  x ≤ 466          
                     $0.50
mariarad [96]2 years ago
3 0
Lets x = <span>number of buttons
</span><span>
Equation:
0.50x + 23.60 = 257
0.50x = 233.4
       x = 466.8

Maximum number of buttons = 466

Answer:
</span><span>D) 466 buttons</span>
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Nataly [62]

Answer:

y = 4x + 14

Step-by-step explanation:

slope-intercept form: y = mx + b

Slope formula: \frac{y2-y1}{x2-x1}

To write the equation in y = mx + b form, we need to find the slope(m) and the y-intercept(b) of the equation.

To find the slope, take two points from the table(in this example I'll use points (0, 14) and (1, 18)) and input them into the slope formula:

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To find the y-intercept, input the values of the slope and one point(in this example I'll use point (1, 18)) into the equation format and solve for b:

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3 0
2 years ago
Assume V and W are​ finite-dimensional vector spaces and T is a linear transformation from V to​ W, T: Upper V right arrow Upper
scZoUnD [109]

Answer:

Thus for the vectors v_1, v_2, v_p there are scalars c_1, c_2, c_p not all zeros, such that c_1v_1 +c_2v_2+... +c_pv_p = 0. It means that the vectors v_1, v_2, v_p are linearly dependent in contradiction with the fact that the vectors form a basis for H. So the assumption that T(v_1), T(v_2),..., T(v_p) are linearly dependent is false, proving the required.  

Step-by-step explanation:

Let B = {v_1 ,v_2,..., v_p} be a basis of H, that is dim H = p and for any v ∈ H there are scalars c_1 , c_2, c_p, such that v = c_1*v_1 + c_2*v_2 +....+ C_p*V_p It follows that  

T(v) = T(c_1*v_1 + c_2v_2 + ••• + c_pV_p) = c_1T(v_1) +c_2T(v_2) + c_pT(v_p)

so T(H) is spanned by p vectors T(v_1),T(v_2), T(v_p). It is enough to prove that these vectors are linearly independent. It will imply that the vectors form a basis of T(H), and thus dim T(H) = p = dim H.  

Assume in contrary that T(v_1 ), T(v_2), T(v_p) are linearly dependent, that is there are scalars c_1, c_2, c_p not all zeros, such that  

c_1T(v_1) + c_2T(v_2) +.... + c_pT(v_p) = 0

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T(c_1v_1+ c_2v_2 ... c_pv_p) = 0  

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Natalka [10]

Step-by-step explanation:

We will learn how to solve proportion problems. We know, the first term (1st) and the fourth term (4th) of a proportion are called extreme terms or extremes, and the second term (2nd) and the third term (3rd) are called middle terms or means.

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example

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5 0
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