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3 years ago

What is the equation of the graph

Mathematics

2 answers:

Mrrafil [7]3 years ago

8 0

To find the equatiom of the graph, we must find the y-intercept and the slope of the line.

Find the y-intercept:

- To find the y-intercept, simply look at the point of where the line crosses the y-axis. In this case, the line seems to cross the point at (0,4), giving the y-intercept of equaling 4.

Find the slope:

- To find the slope of the line, take one of the points and use the "rise/run" method, and find the next consecutive point. In this case, we'll take point (4,1) as an example. The next consecutive point is @ (0,4). So, we'll count 3 units up and 4 units left. So the slope of this line will be -3/4. (It is negative because we counted to the left. However, POSITIVE 3/4 would have left us with an entirely different slope and the line would be structurally different ((Seriously, try it out for yourself, if you don't understand what I am talking about!))).

Now that we have our slope and y-intercept, let's use the slope-intercept form so that we can get our equation.

- Slope-Intercept Form:
• y = mx + b
□ Whereas, "m" equals the slope of the line, and "b" equals the y-intercept of the line.

- Let's plug in the values of the y-intercept and the slope into the equation.

** y = -3/4x + 4 **

So, the equation for this line is "y = -3/4x + 4".

Katen [24]3 years ago

6 0

I assume you want it in slop-intercept form.
y = 3/4x + y-intercept (the graph isn't labeled)
If you just want to find the slope of the graph, it would be 3/4

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Fynjy0 [20]

Answer:

0.02% probability that the average amount billed on the sample bills is greater than $500.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 465, \sigma = 300, n = 900, s = \frac{300}{\sqrt{900}} = 10$ .

What is the probability that the average amount billed on the sample bills is greater than $500?

This probability is 1 subtracted by the pvalue of Z when $X = 500$ . So

$Z = \frac{X - \mu}{s}$

$Z = \frac{500 - 465}{10}$

$Z = 3.5$

$Z = 3.5$ has a pvalue of 0.9998.

So there is a 1-0.9998 = 0.0002 = 0.02% probability that the average amount billed on the sample bills is greater than $500.

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