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Vaselesa [24]
3 years ago
13

What is the equation of the graph

Mathematics
2 answers:
Mrrafil [7]3 years ago
8 0
To find the equatiom of the graph, we must find the y-intercept and the slope of the line.

Find the y-intercept:

- To find the y-intercept, simply look at the point of where the line crosses the y-axis. In this case, the line seems to cross the point at (0,4), giving the y-intercept of equaling 4.

Find the slope:

- To find the slope of the line, take one of the points and use the "rise/run" method, and find the next consecutive point. In this case, we'll take point (4,1) as an example. The next consecutive point is @ (0,4). So, we'll count 3 units up and 4 units left. So the slope of this line will be -3/4. (It is negative because we counted to the left. However, POSITIVE 3/4 would have left us with an entirely different slope and the line would be structurally different ((Seriously, try it out for yourself, if you don't understand what I am talking about!))).

Now that we have our slope and y-intercept, let's use the slope-intercept form so that we can get our equation.

- Slope-Intercept Form:
• y = mx + b
□ Whereas, "m" equals the slope of the line, and "b" equals the y-intercept of the line.

- Let's plug in the values of the y-intercept and the slope into the equation.

** y = -3/4x + 4 **

So, the equation for this line is "y = -3/4x + 4".
Katen [24]3 years ago
6 0
I assume you want it in slop-intercept form.
y = 3/4x + y-intercept (the graph isn't labeled)
If you just want to find the slope of the graph, it would be 3/4
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Step-by-step explanation:

\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2}  t^2+1 \ \text{dt} = \ ?

We can use Part I of the Fundamental Theorem of Calculus:

  • \displaystyle\frac{d}{dx} \int\limits^x_a \text{f(t) dt = f(x)}

Since we have two functions as the limits of integration, we can use one of the properties of integrals; the additivity rule.

The Additivity Rule for Integrals states that:

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We can use this backward and break the integral into two parts. We can use any number for "b", but I will use 0 since it tends to make calculations simpler.

  • \displaystyle \frac{d}{dx} \int\limits^0_{2x} t^2+1 \text{ dt} \ + \ \frac{d}{dx} \int\limits^{x^2}_0 t^2+1 \text{ dt}

We want the variable to be the top limit of integration, so we can use the Order of Integration Rule to rewrite this.

The Order of Integration Rule states that:

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We can use this rule to our advantage by flipping the limits of integration on the first integral and adding a negative sign.

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Now we can take the derivative of the integrals by using the Fundamental Theorem of Calculus.

When taking the derivative of an integral, we can follow this notation:

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For the first term, replace \text{t} with 2x, and apply the chain rule to the function. Do the same for the second term; replace

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Simplify the expression by distributing 2 and 2x inside their respective parentheses.

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Rearrange the terms to be in order from the highest degree to the lowest degree.

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This is the derivative of the given integral, and thus the solution to the problem.

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