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2 years ago

9

A rectangular park has an area of 250 square feet. The length of the park is 7 feet more then twice the width, w of the park. Wh

ich equations, in terms of w, model this situation

2 answers:

Andru [333]2 years ago

5 0

Area = length * width

width = w

length = 2w+7

A = (2w+7) * w

250 =2w^2+7w

0 = 2w^2 +7w-250

Strike441 [17]2 years ago

4 0

w is the width, hence length is 2w + 7 ( 7 more than twice the width )

area = length × width = w( 2w + 7 ) = 250

2w² + 7w - 250 = 0 ← in standard form

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The school production of Our Town' was a big success. For opening night. 434 tickets were sold. Students paid $4.00 each, while

Alex73 [517]

Answer:

286 students attended

148 non students attended

Step-by-step explanation:

Given

$Tickets = 434$

$Students = \$4.00$

$Non-Students = \$6.00$

$Total = \$2032.00$

Solving (a): Number of students

Represent students with S and non students with N

So:

$S + N = 434$ --- (1)

$4S + 6N = 2032$ --- (2)

Make N the subject of formula in (1)

$N = 434 - S$

Substitute 434 - S for N in (2)

$4S +6(434 - S) = 2032$

Open Bracket

$4S + 2604 - 6S = 2032$

Collect Like Terms

$4S - 6S = 2032 - 2604$

$-2S = -572$

Divide through by -2

$S = 286$

<em>Hence; 286 students attended</em>

Solving (b):

Recall that

$N = 434 - S$

$N = 434 - 286$

$N = 148$

<em>148 non students attended</em>

4 0

2 years ago

Solve for x. 5 1/2 ≥ 1.6x<br> x ≥3 7/16<br> x ≤ 3 7/16<br> x ≥ 8 4/5<br> x ≤ 8 4/5

11Alexandr11 [23.1K]

Answer:

x < 3 7/16

Step-by-step explanation:

8 0

2 years ago

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The manufacturer of an electronic device claims that the probability of the device failing during the warranty period is 0.005.

Zielflug [23.3K]

Answer:

The value is $P(X \ge 15) = 0.5$

Step-by-step explanation:

From the question we are told that

The probability of the device failing during the warranty period is $p = 0.005$

The sample size is $n = 3000$

The random variable considered is x = 15

Generally this is distribution is binomial given the fact that there is only two out comes hence

X which is a variable representing a randomly selected selected electronic follows a binomial distribution i.e

$X \~ \ B(n , p)$

Now the mean is mathematically evaluated as

$\mu = n * p$

=> $\mu = 3000 * 0.005$

=> $\mu =15$

The standard deviation is mathematically represented as

$\sigma = \sqrt{np(1 -p )}$

=> $\sigma = \sqrt{3000 * 0.005 * (1 - 0.005 )}$

=> $\sigma = 3.86$

Now given that n is very large, then it mean that we can successfully apply normal approximation on this binomial distribution

So

$P(X \ge 15) = P( \frac{X - \mu}{\sigma } \ge \frac{x - \mu}{\sigma } )$

Now applying Continuity Correction we have

$P(X \ge (15-0.5)) = P( \frac{X - \mu}{\sigma } > \frac{(15 -0.5) - 15}{3.86 } )$

Generally $\frac{X - \mu}{\sigma } = Z (The \ standardized \ value \ of \ X)$

$P(X \ge (15-0.5)) = P(Z >-0.130 )$

From the z-table

$P(Z >-0.130 ) =0.5$

Thus

$P(X \ge 15) = 0.5$

7 0

3 years ago

Help pls don not under stand

m_a_m_a [10]

The expected value of health care without insurance is $437.25.

The expected value of health care with insurance is $1,636.40.

<h3>What are the expected values?</h3>

The expected values can be determined by multiplying the respective probabilities by its associated costs.

The expected value of health care without insurance = (1 x 0) + (0.32 x 1050) + (0.45 x $225) = $437.25.

The expected value of health care with insurance = (1 x 1580) + (0.32 x 75) + (0.45 x $72) = $1,636.40.

To learn more about multiplication, please check: brainly.com/question/13814687

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1 year ago

Who would have a difficult time responding to this survey question? Select all that apply.

I am Lyosha [343]

Answer:

18 and 65

Step-by-step explanation:

under 18 would be 17 and under, therefore not including 18 year olds. obviously they are not 19 yet either, so they wouldn't fall into either category, therefore they may be unsure of what to answer.

same with 65 year olds; they are more than 64 year old, but not yet /over/ 65, therefore they would not fit into either category either.

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3 years ago

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