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olga_2 [115]
4 years ago
10

How much does 4 5/7 kg of candy cost if 5/6 kg costs $7.50

Mathematics
1 answer:
Aliun [14]4 years ago
7 0

Answer:

It costs $42.43

Step-by-step explanation:

Lets explain how to solve the problem

- The cost of \frac{5}{6} kilogram of candy is $7.5

- We need to find the cost of 4\frac{5}{7} kilogram

We  can use the ratio to find the answer

======= Dollar   :    Kilogram

======= 7.5        :    \frac{5}{6}

=======  c           :    4\frac{5}{7}  

By using cross multiplication

∴ c × \frac{5}{6} = 7.5 × 4\frac{5}{7}

∵ 4\frac{5}{7} = \frac{4*7+5}{7}

∴ 4\frac{5}{7} = \frac{33}{7}

∴ c × \frac{5}{6} = 7.5 × \frac{33}{7}

∴ c × \frac{5}{6} = \frac{495}{14}

Divide both sides by \frac{5}{6}

∴ c = \frac{495}{14} ÷ \frac{5}{6}

Change the division sign to multiplication sign and reciprocal the

fraction after the division sign

∴ c = \frac{495}{14} × \frac{6}{5}

∴ c = \frac{297}{7} = 42.43 dollars

∵ c represents the cost of 4\frac{5}{7} kg

∴ It costs $42.43

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Read 2 more answers
Needs answers <br> Will mark brainliest
Elden [556K]

QUESTION 1:

Required angles are: m<2=75°, m<3=75°, m<4= 105°, m<5= 105°, m<6=75°, m<7=75°, m<8=105°

QUESTION 2:

Required angles are: m<1=100° m<2=80°, m<4= 100°, m<5= 100°, m<6=80°, m<7=80°, m<8=100°

Step-by-step explanation:

Question 1:

if m<1 =105°

We need to find the remaining angles.

The corresponding angles of a traversal are same. so the corresponding angle of <1 is angle 5 So, m<5 = 105°

The vertical angles are also equal. so, vertical angle of <1 is <4. So, m<4 = 105°

Vertical angles of m<5 is m<8 so, m<8=105°

m<1 and m<2 are supplementary angles of each other so their sum will be equal to 180°

So, m<1+m<2=180

105+m<2=180

m<2=75°

Same goes for m<3 and m<4 so, m<3 = 75°

m<5 and m<6 so, m<6 = 75°

m<7 and m<8 so, m<7= 75°

So, required angles are: m<2=75°, m<3=75°, m<4= 105°, m<5= 105°, m<6=75°, m<7=75°, m<8=105°

Question No 2

if m<3=80°

We need to find the remaining angles.

The corresponding angles of a traversal are same. so the corresponding angle of <3 is angle 7 So, m<7 = 80°

The vertical angles are also equal. so, vertical angle of <3 is <2. So, m<2 = 80°

The Vertical angle of <7 is <6 so, m<6= 80°.

m<1 and m<2 are supplementary angles of each other so their sum will be equal to 180°

So, m<1+m<2=180

m<1+80=180

m<1=100°

Same goes for m<3 and m<4 so, m<4 = 100°

m<5 and m<6 so, m<5 = 100°

m<7 and m<8 so, m<8= 100°

So, required angles are: m<1=100° m<2=80°, m<4= 100°, m<5= 100°, m<6=80°, m<7=80°, m<8=100°

Keywords: Traversal of parallel lines

Learn more about traversal of parallel lines at:

  • brainly.com/question/1598227
  • brainly.com/question/3227215
  • brainly.com/question/10483199

#learnwithBrainly

3 0
4 years ago
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