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olga_2 [115]
3 years ago
10

How much does 4 5/7 kg of candy cost if 5/6 kg costs $7.50

Mathematics
1 answer:
Aliun [14]3 years ago
7 0

Answer:

It costs $42.43

Step-by-step explanation:

Lets explain how to solve the problem

- The cost of \frac{5}{6} kilogram of candy is $7.5

- We need to find the cost of 4\frac{5}{7} kilogram

We  can use the ratio to find the answer

======= Dollar   :    Kilogram

======= 7.5        :    \frac{5}{6}

=======  c           :    4\frac{5}{7}  

By using cross multiplication

∴ c × \frac{5}{6} = 7.5 × 4\frac{5}{7}

∵ 4\frac{5}{7} = \frac{4*7+5}{7}

∴ 4\frac{5}{7} = \frac{33}{7}

∴ c × \frac{5}{6} = 7.5 × \frac{33}{7}

∴ c × \frac{5}{6} = \frac{495}{14}

Divide both sides by \frac{5}{6}

∴ c = \frac{495}{14} ÷ \frac{5}{6}

Change the division sign to multiplication sign and reciprocal the

fraction after the division sign

∴ c = \frac{495}{14} × \frac{6}{5}

∴ c = \frac{297}{7} = 42.43 dollars

∵ c represents the cost of 4\frac{5}{7} kg

∴ It costs $42.43

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Neporo4naja [7]

Answer:

Step-by-step explanation:

Rule for the transformations has been given as,

T_{(5, -0.05)o\text{R}(0, 180)}(x,y) defines the rules as the translation by 5 units right and 0.5 units down followed by rotation of the triangle by 180° about the origin.

In other words,

Rule for translation:

F(x, y) → F"(x + 5, y - 0.5)

Followed by the rotation of 180° about the origin,

Rule of rotation,

F"(x', y') → F'(-x, -y)

Following these rules coordinates of the new triangle F'G'H' can be obtained.

3 0
3 years ago
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victus00 [196]

Answer:

6 miles

Step-by-step explanation:

From the above question:

Stan ran 4 and StartFraction 7 Over 10 EndFraction miles

The number of miles stan ran =

4 7/10 miles

We are also told that this number of miles was 1 and StartFraction 3 Over 10 EndFraction fewer miles than Matt ran.

Let the number of miles Matt ran = m

Hence,

4 7/10 miles = m - 1 3/10

m = 4 7/10 + 1 3/10

m = (4 + 1) + ( 7/10 + 3/10)

m = 5 + (7 + 3/10)

m = 5 + (10/10)

m = 5 + 1

m = 6 miles

Therefore, the number rod miles Matt ran was 6 miles

7 0
2 years ago
5.
andrew-mc [135]

Answer:

The  angle of depression from Platform A to Platform B is 43.1^{\circ}

Step-by-step explanation:

Refer the attached figure

The horizontal distance between the  platforms is 500 feet i.e. BC = 500

The length of the zip-line is 685 feet i.e. AB = 685

We are supposed to find the  angle of depression from Platform A to Platform B

Hypotenuse = 685

Base = 500

Cos \theta = \frac{Base}{Hypotenuse}\\Cos \theta = \frac{500}{685}\\\theta = cos^{-1}(\frac{500}{685})\\\theta = 43.11^{\circ}

Hence  the  angle of depression from Platform A to Platform B is 43.1^{\circ}

4 0
3 years ago
Point D is on segment BC, Segment BC measures Bx
Nostrana [21]

Answer:

144 units

Step-by-step explanation:

3x + 8 + 4x + 10 = 8x

7x + 18 = 8x

8x - 7x = 18

x = 18

8x is length of BC

8 × 18 is length of BC

144 units

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What is 0.58 as a fraction
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0.58
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