Answer:
5a^4+a^2b−6b^2
Step-by-step explanation:
1. Use the FOIL method: (a+b)(c+d)=ac+ad+bc+bd.
5a^4+6a^2b−5ba^2−6b^2
2. Collect like terms.
5a^4+(6a^2b−5a^2b)−6b^2
3. Simplify.
5a^4+a^2b−6b^2
<em>AC bisects ∠BAD, => ∠BAC=∠CAD ..... (1)</em>
<em>thus in ΔABC and ΔADC, ∠ABC=∠ADC (given), </em>
<em> ∠BAC=∠CAD [from (1)],</em>
<em>AC (opposite side side of ∠ABC) = AC (opposite side side of ∠ADC), the common side between ΔABC and ΔADC</em>
<em>Hence, by AAS axiom, ΔABC ≅ ΔADC,</em>
<em>Therefore, BC (opposite side side of ∠BAC) = DC (opposite side side of ∠CAD), since (1)</em>
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Hence, BC=DC proved.
Answer: The answer is 29, because that 29 would be the outlier of the numbers.
Step-by-step explanation:
Answer:
dodecagon
Step-by-step explanation:
