Answer:
1/5x=3/4hour
so since 5 times 1/5=1 then
find x
multiply both sides by 5
x=15/4 hour=3 and 3/4 hour=3 hour and 45 mins ← <u>Answer </u>
* <em>Hopefully this helps:) Mark me the brainliest:)!!</em>
<em>∫ 234483279c20∫</em>
Answer:
complementary
Step-by-step explanation:
the exact diagram is below
Answer:
y = 2M - x
Step-by-step explanation:
M = (x + y)/2 Multiply both sides by 2
2M = x + y Subtract x from each side
y = 2M - x
Answer:
![{\bf e}_{1}=\frac{(-1,1,0)}{\lVert (-1,1,0) \rVert}=\left(\frac{-1}{\sqrt{2}},\frac{1}{\sqrt{2}},0\right)](https://tex.z-dn.net/?f=%7B%5Cbf%20e%7D_%7B1%7D%3D%5Cfrac%7B%28-1%2C1%2C0%29%7D%7B%5ClVert%20%28-1%2C1%2C0%29%20%5CrVert%7D%3D%5Cleft%28%5Cfrac%7B-1%7D%7B%5Csqrt%7B2%7D%7D%2C%5Cfrac%7B1%7D%7B%5Csqrt%7B2%7D%7D%2C0%5Cright%29)
![{\bf e}_{2}=\frac{{\bf v}_{2}-({\bf v}_{2}\cdot {\bf e}_{1}) {\bf e}_{1}}{\lVert {\bf v}_{2}-({\bf v}_{2}\cdot {\bf e}_{1}) {\bf e}_{1} \rVert}=\left(\frac{1}{\sqrt{6}},\frac{1}{\sqrt{6}},\sqrt{\frac{2}{3}}\right)](https://tex.z-dn.net/?f=%7B%5Cbf%20e%7D_%7B2%7D%3D%5Cfrac%7B%7B%5Cbf%20v%7D_%7B2%7D-%28%7B%5Cbf%20v%7D_%7B2%7D%5Ccdot%20%7B%5Cbf%20e%7D_%7B1%7D%29%20%7B%5Cbf%20e%7D_%7B1%7D%7D%7B%5ClVert%20%7B%5Cbf%20v%7D_%7B2%7D-%28%7B%5Cbf%20v%7D_%7B2%7D%5Ccdot%20%7B%5Cbf%20e%7D_%7B1%7D%29%20%7B%5Cbf%20e%7D_%7B1%7D%20%5CrVert%7D%3D%5Cleft%28%5Cfrac%7B1%7D%7B%5Csqrt%7B6%7D%7D%2C%5Cfrac%7B1%7D%7B%5Csqrt%7B6%7D%7D%2C%5Csqrt%7B%5Cfrac%7B2%7D%7B3%7D%7D%5Cright%29)
![{\bf e}_{3}=\frac{{\bf v}_{3}-({\bf v}_{3}\cdot{\bf e_{1}}){\bf e}_{1}-({\bf v}_{3}\cdot {\bf e}_{2}){\bf e}_{2}}{\lVert {\bf v}_{3}-({\bf v}_{3}\cdot{\bf e_{1}}){\bf e}_{1}-({\bf v}_{3}\cdot {\bf e}_{2}){\bf e}_{2} \rVert}=\left(-\frac{1}{\sqrt{3}},-\frac{1}{\sqrt{3}},\frac{1}{\sqrt{3}}\right)](https://tex.z-dn.net/?f=%7B%5Cbf%20e%7D_%7B3%7D%3D%5Cfrac%7B%7B%5Cbf%20v%7D_%7B3%7D-%28%7B%5Cbf%20v%7D_%7B3%7D%5Ccdot%7B%5Cbf%20e_%7B1%7D%7D%29%7B%5Cbf%20e%7D_%7B1%7D-%28%7B%5Cbf%20v%7D_%7B3%7D%5Ccdot%20%7B%5Cbf%20e%7D_%7B2%7D%29%7B%5Cbf%20e%7D_%7B2%7D%7D%7B%5ClVert%20%7B%5Cbf%20v%7D_%7B3%7D-%28%7B%5Cbf%20v%7D_%7B3%7D%5Ccdot%7B%5Cbf%20e_%7B1%7D%7D%29%7B%5Cbf%20e%7D_%7B1%7D-%28%7B%5Cbf%20v%7D_%7B3%7D%5Ccdot%20%7B%5Cbf%20e%7D_%7B2%7D%29%7B%5Cbf%20e%7D_%7B2%7D%20%5CrVert%7D%3D%5Cleft%28-%5Cfrac%7B1%7D%7B%5Csqrt%7B3%7D%7D%2C-%5Cfrac%7B1%7D%7B%5Csqrt%7B3%7D%7D%2C%5Cfrac%7B1%7D%7B%5Csqrt%7B3%7D%7D%5Cright%29)
Step-by-step explanation:
We have the basis of
. From this basis we want to determine another orthonormal basis
of
.
The first step is to define
as:
![{\bf e}_{1}=\frac{(-1,1,0)}{\lVert (-1,1,0) \rVert}=\left(\frac{-1}{\sqrt{2}},\frac{1}{\sqrt{2}},0\right)](https://tex.z-dn.net/?f=%7B%5Cbf%20e%7D_%7B1%7D%3D%5Cfrac%7B%28-1%2C1%2C0%29%7D%7B%5ClVert%20%28-1%2C1%2C0%29%20%5CrVert%7D%3D%5Cleft%28%5Cfrac%7B-1%7D%7B%5Csqrt%7B2%7D%7D%2C%5Cfrac%7B1%7D%7B%5Csqrt%7B2%7D%7D%2C0%5Cright%29)
Now define
by:
![{\bf e}_{2}=\frac{{\bf v}_{2}-({\bf v}_{2}\cdot {\bf e}_{1}) {\bf e}_{1}}{\lVert {\bf v}_{2}-({\bf v}_{2}\cdot {\bf e}_{1}) {\bf e}_{1} \rVert}=\left(\frac{1}{\sqrt{6}},\frac{1}{\sqrt{6}},\sqrt{\frac{2}{3}}\right)](https://tex.z-dn.net/?f=%7B%5Cbf%20e%7D_%7B2%7D%3D%5Cfrac%7B%7B%5Cbf%20v%7D_%7B2%7D-%28%7B%5Cbf%20v%7D_%7B2%7D%5Ccdot%20%7B%5Cbf%20e%7D_%7B1%7D%29%20%7B%5Cbf%20e%7D_%7B1%7D%7D%7B%5ClVert%20%7B%5Cbf%20v%7D_%7B2%7D-%28%7B%5Cbf%20v%7D_%7B2%7D%5Ccdot%20%7B%5Cbf%20e%7D_%7B1%7D%29%20%7B%5Cbf%20e%7D_%7B1%7D%20%5CrVert%7D%3D%5Cleft%28%5Cfrac%7B1%7D%7B%5Csqrt%7B6%7D%7D%2C%5Cfrac%7B1%7D%7B%5Csqrt%7B6%7D%7D%2C%5Csqrt%7B%5Cfrac%7B2%7D%7B3%7D%7D%5Cright%29)
Now define
by :
![{\bf e}_{3}=\frac{{\bf v}_{3}-({\bf v}_{3}\cdot{\bf e_{1}}){\bf e}_{1}-({\bf v}_{3}\cdot {\bf e}_{2}){\bf e}_{2}}{\lVert {\bf v}_{3}-({\bf v}_{3}\cdot{\bf e_{1}}){\bf e}_{1}-({\bf v}_{3}\cdot {\bf e}_{2}){\bf e}_{2} \rVert}=\left(-\frac{1}{\sqrt{3}},-\frac{1}{\sqrt{3}},\frac{1}{\sqrt{3}}\right)](https://tex.z-dn.net/?f=%7B%5Cbf%20e%7D_%7B3%7D%3D%5Cfrac%7B%7B%5Cbf%20v%7D_%7B3%7D-%28%7B%5Cbf%20v%7D_%7B3%7D%5Ccdot%7B%5Cbf%20e_%7B1%7D%7D%29%7B%5Cbf%20e%7D_%7B1%7D-%28%7B%5Cbf%20v%7D_%7B3%7D%5Ccdot%20%7B%5Cbf%20e%7D_%7B2%7D%29%7B%5Cbf%20e%7D_%7B2%7D%7D%7B%5ClVert%20%7B%5Cbf%20v%7D_%7B3%7D-%28%7B%5Cbf%20v%7D_%7B3%7D%5Ccdot%7B%5Cbf%20e_%7B1%7D%7D%29%7B%5Cbf%20e%7D_%7B1%7D-%28%7B%5Cbf%20v%7D_%7B3%7D%5Ccdot%20%7B%5Cbf%20e%7D_%7B2%7D%29%7B%5Cbf%20e%7D_%7B2%7D%20%5CrVert%7D%3D%5Cleft%28-%5Cfrac%7B1%7D%7B%5Csqrt%7B3%7D%7D%2C-%5Cfrac%7B1%7D%7B%5Csqrt%7B3%7D%7D%2C%5Cfrac%7B1%7D%7B%5Csqrt%7B3%7D%7D%5Cright%29)
Isolate the variable by dividing each side by factors that don't contain the ...
y variable=139x/ 5 2/5-
x variable =5y/139+2/139