Answer:
1/(5^12 * 32^3 * 9^15)
Step-by-step explanation:
5^-12 = 1/(5^12)
32^-3 = 1/(32^3)
9^-15 = 1/(9^15)
1/(5^12) * 1/(32^3) * 1/(9^15) = 1/(5^12 * 32^3 * 9^15)
M∠ADB + m∠BDC = m∠ADC [<span>angle addition postulate]
x + x + 10 = 60
2x + 10 = 60
2x = 60 - 10
2x = 50
x = 50/2
x = 25
a
m</span>∠ADB = x = 25°
b
m∠BDC = x + 10 = 25 + 10 = 35°
Answer: D, 6km/hr.
Step-by-step explanation:
Heather can finish a 12-kilometer race in 2 hours, and now we have to find how many kilometers she can ride/run at in 1 hour.
How many hours can Heather run in 1 hour? To solve that, we can use the equation 12 ÷ 2.
12 ÷ 2 = 6.
Therefore, if Heather keeps her pace constant, then her rate will be 6km/hr, or D.
Answer:
A. 168 units³
Step-by-step explanation:
volume = area of bas × height
volume = (6)(7)/2 × 8
volume = 168 units³
Answer: The answer is 1296
