Answer:
3.9
Step-by-step explanation:
Given the data:
Payout ($) (x) : 0 2 4 8 10
Probability p(x) : 0.35 0.2 0.1 0.2 0.15
The expected winning ; E(X) = Σ(x * p(x))
Σ(x * p(x)) = (0*0.35)+(2*0.2)+(4*0.1)+(8*0.2)+(10*0.15)
= 0 + 0.4 + 0.4 + 1.6 + 1.5
= 3.9
Answer:
x=30
Step-by-step explanation:
you distribute the negative to 2x and 19
3x+4-2x-19=15
then you combine like terms
x-15=15
you add 15 to both sides
x=30
DONT CLCIK THE LINK PLEASE REPORT IT
Answer:
Step-by-step explanation:
Complete Question:
Chapter 6, Section 1-D, Exercise 009 Is a Normal Distribution Appropriate? In each case below, is the sample size large enough so that the sample proportions follow a normal distribution?
a) n=600 p=0.2
b) n=20, p=0.4
if np=10 and npq=10 then the data follows normal distribution
a) np= 120,
q= 1-0.2= 0.8
npq= 600 ×0.2×0.4 = 48
Normal distribution is appropriate and sample size is large enough
b) np= 8
q= 1-0.4= 0.6
npq= 20 × 0.4×0.6= 4.8
sample size is not large enough so normal distribution is not appropriate.
Answer:
Step-by-step explanation:
Given that the random variable X is normally distributed, with
mean = 50 and standard deviation = 7.
Then we have z= 
Using this and normal table we find that
a) 
b) When z=0.02
we get
c) 90th percentile z value =1.645
90th percentile of X 
