Answer:
* Elimination; a coefficient in Equation I is an integer multiple of a coefficient in Equation II.
* Elimination; a coefficient in Equation II is an integer multiple of a coefficient in Equation I.
Step-by-step explanation:
Equation I: 4x − 5y = 4
Equation II: 2x + 3y = 2
These equation can only be solved by Elimination method
Where to Eliminate x :
We Multiply Equation I by a coefficient of x in Equation II and Equation II by the coefficient of x in Equation I
Hence:
Equation I: 4x − 5y = 4 × 2
Equation II: 2x + 3y = 2 × 4
8x - 10y = 20
8x +12y = 6
Therefore, the valid reason using the given solution method to solve the system of equations shown is:
* Elimination; a coefficient in Equation I is an integer multiple of a coefficient in Equation II.
* Elimination; a coefficient in Equation II is an integer multiple of a coefficient in Equation I.
It will be an underestimate the answer is 43 I hoped that helped?
Answer:
320 miles
Step-by-step explanation:
c=178
subtract the base fee of 50 from c- you get 128
Divide 128 by the 0.40 rate to get m by itself
m then equals 320
Answer:
I don't know the value of either, could you add more information?
Step-by-step explanation:
I'd be glad to help.
Answer:
a=5, b=-2
Step-by-step explanation:
If you simplify the equation, you get:
3ax +6 -4x -4b - 11x - 14 = 0 =>
3ax - 15x -4b -8 = 0
group together x's and constants:
(3a-15)x -8 -4b = 0
To make this 0 for all x, we have to find an a such that 3a-15 = 0 and b such that -8-4b = 0. this leads to a=5, b=-2
