The first 6 is equal to 6,000. The second 6 is equal to 600. 6,000 is 10 times greater than 600.
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<span>1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12
One die can show the values 1-6, while the other die can only show 0 or 6. So the possible totals are 1 through 6 plus 0 and 1 through 6 plus 6. Written out, one-by-one, this gives:
1+0 = 1
2+0 = 2
3+0 = 3
4+0 = 4
5+0 = 5
6+0 = 6
1+6 = 7
2+6 = 8
3+6 = 9
4+6 = 10
5+6 = 11
6+6 = 12</span>
21-7=14 is a relate subtraction problem
Answer:
You can try the first one which is the value it can be 5 and the second one can be 4. I can be wrong.
Step-by-step explanation:
