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umka2103 [35]
3 years ago
10

A ​used-car dealership buys a car for ​$2700 and then sells it for ​$3900. What is the percent​ increase?

Mathematics
1 answer:
uranmaximum [27]3 years ago
7 0

Answer:

400/9 = 44. 444... or 44.5

Step-by-step explanation:

difference in price/original price * 100

1200/2700 * 100

4/9 * 100

= 400/9

<em>percentage is 44.5 %</em>

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Sin (x/4) = 1/2
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So, your final answer is 180

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1. Find the 90% Cl for the population mean if sample
Elden [556K]

Answer:

The answer is below

Step-by-step explanation:

1)

mean (μ) = 12, SD(σ) = 2.3, sample size (n) = 65

Given that the confidence level (c) = 90% = 0.9

α = 1 - c = 0.1

α/2 = 0.05

The z score of α/2 is the same as the z score of 0.45 (0.5 - 0.05) which is equal to 1.65

The margin of error (E) is given as:

E=Z_{\frac{\alpha}{2} }*\frac{\sigma}{\sqrt{n} } =1.65*\frac{2.3}{\sqrt{65} } =0.47

The confidence interval = μ ± E = 12 ± 0.47 = (11.53, 12.47)

2)

mean (μ) = 23, SD(σ) = 12, sample size (n) = 45

Given that the confidence level (c) = 88% = 0.88

α = 1 - c = 0.12

α/2 = 0.06

The z score of α/2 is the same as the z score of 0.44 (0.5 - 0.06) which is equal to 1.56

The margin of error (E) is given as:

E=Z_{\frac{\alpha}{2} }*\frac{\sigma}{\sqrt{n} } =1.56*\frac{12}{\sqrt{45} } =2.8

The confidence interval = μ ± E = 23 ± 2.8 = (22.2, 25.8)

8 0
3 years ago
(PLESE HELP) Factor the following expression. Simplify your answer.
mars1129 [50]

The factor of the expression 5p(p + 2)^{\frac{2}{3} }  + 4(p + 2)^{\frac{1}{3} } is(p + 2)^{\frac{2}{3} } (5p^{3}  + 10p^{2}  + 20p + 4)

To answer the question, we need to know what factorization is

<h3>What is factorization?</h3>

Factorization is the process of breaking down an expressing into a simpler form containing its factors.

Since

5p(p + 2)^{\frac{2}{3} }  + 4(p + 2)^{\frac{1}{3} }

Since (p + 2)^{\frac{1}{3} } is common, we factor it out. So, we have

(p + 2)^{\frac{2}{3} } (5p(p + 2)^{2}  + 4)

Expanding the bracket, we have

(p + 2)^{\frac{2}{3} } (5p(p^{2}  + 2p + 4) + 4) = (p + 2)^{\frac{2}{3} } (5p^{3}  + 10p^{2}  + 20p + 4)

So, the factor of the expression 5p(p + 2)^{\frac{2}{3} }  + 4(p + 2)^{\frac{1}{3} } is(p + 2)^{\frac{2}{3} } (5p^{3}  + 10p^{2}  + 20p + 4)

Learn more about factorization here:

brainly.com/question/11579257

#SPJ1

8 0
2 years ago
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