Answer:
There is sufficient evidence at the 0.05 level
Null hypothesis ; H0 : p = 0.47
Alternative hypothesis : H1 : p ≠ 0.47
Step-by-step explanation:
percentage favoring construction of adjoining community = 47%
level = 0.05
To determine if the 0.05 confidence level is enough to support the major's claim we have to state the Null and alternative hypothesis
Null hypothesis ; H0 : p = 0.47
Alternative hypothesis : H1 : p ≠ 0.47
There is a problem,in order to solve this u need a cordanite bride for them to go on.
Answer
the answer is P=7.8
Step-by-step explanation:
P=14.7e -0.21x
X=14.7e (-0.63)
take the natrual log of both sides
1n(P)=1n(14.7e(-.63)
1n(P)=1n(14.7)-.63
(because ln(e^a) = a)
1n(P)=2.688 - .63
1n(P)=2.058
P=e 2.058
P=7.8
Answer: Its True
Step-by-step explanation:
The statement is true because the Percentages are preferred and also they are easier to compare than counts.
Answer:
A)σ = 15.37 miles per hour
B) σ = 55.10 miles per hour
C) 39.73 miles per hour
Step-by-step explanation:
Formula for standard deviation is;
σ = √(Σ(x - μ)²)/(n - 1)
A) For large wild cats;
μ = Σx/n = (70 + 40 + 30 + 40 + 35 + 35 + 35 + 35 + 10)/9 = 36.67
σ = √((70 - 36.67)² + (40 - 36.67)² + (30 - 36.67)² + (40 - 36.67)² + (35 - 36.67)² + (35 - 36.67)² + (35 - 36.67)² + (35 - 36.67)² + (10 - 36.67)²)/(9 - 1)
σ = √236.1139
σ = 15.37
B) For various birds;
μ = Σx/n = (218 + 106 + 97 + 56 + 66 + 39 + 55 + 32 + 54 + 20 + 25 + 25)/12
μ = 66.0833
σ = √((218 - 66.0833)² + (106 - 66.0833)² + (97 - 66.0833)² + (56 - 66.0833)² + (66 - 66.0833)² + (39 - 66.0833)² + (55 - 66.0833)² + (32 - 66.0833)² + (54 - 66.0833)² + (20 - 66.0833)² + (25 - 66.0833)² + (25 - 66.0833)²)/(12 - 1)
σ = √3035.72
σ = 55.10
C) difference in standard deviations = 55.10 - 15.37 = 39.73 miles per hour
