Question

What is the value of 3x to the second power + 4y to the second power if x=2 and y=-3?​

Answer 1

Answer: The value is 48

Step-by-step explanation:

Given the following expression:

$3x^2+4y^2$

You need to substitute the values of each variables provided in the exercise into this expression. You can observe that the value of the variable "x" and  the value of the variable "y" are:

$x=2 \\ y=-3$

Therefore, substituting values, you get:

$3x^2+4y^2=3(2)^2+4(-3)^2=3(4)+4(9)=12+36=48$

 

Answer 2

Answer: 3(2)^2 + 4(3)^2

Step-by-step explanation:

First do what is replacing the variables by changing X to 2 and Y to -3

3(2)^2 + 4(-3)^2 = 3(4) + 4(9) = 12 + 36 = 48