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Setler79 [48]
3 years ago
12

find the number of terms in an AP given that its first and last terms are 13 and - 23 respectively and that its common differenc

e is -2 1/4​
Mathematics
1 answer:
Leokris [45]3 years ago
5 0

Answer:

<u>There are 17 terms in the sequence</u>

Step-by-step explanation:

<u>Arithmetic Sequence </u>

An arithmetic sequence is a list of numbers with a definite pattern by which each term is calculated by adding or subtracting a constant number called common difference to the previous term. If n is the number of the term, then:

a_n=a_1+(n-1)r

Where an is the nth term, a1 is the first term, and r is the common difference.

In the problem at hand, we are given the first term a1=13, the last term an=-23, and the common difference r=-2 1/4. Let's solve the equation for n:

\displaystyle n=1+\frac{a_n-a_1}{r}

We need to express r as an improper or proper fraction:

\displaystyle r=-2\frac{1}{4}=-2-\frac{1}{4}=-\frac{9}{4}

Substituting:

\displaystyle n=1+\frac{-23-13}{-\frac{9}{4}}

\displaystyle n=1+\frac{-36}{-\frac{9}{4}}

\displaystyle n=1+36*\frac{4}{9}=17

n=17

There are 17 terms in the sequence

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The probability of drawing a red candy at random from a bag of 25 candies is \dfrac{2}{5}.

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The probability of randomly drawing a red candy from the bag after removing 5 candies from the bag.

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A box contains $7.45 in nickels, dimes, and quarters. There are 43 coins in all, and the sum of the numbers of nickels and dimes
kari74 [83]

Answer:

<em>Number of nickels = 6</em>

<em>Number of dimes = 14</em>

<em>Number of quarters = 23</em>

<em></em>

Step-by-step explanation:

Total number of coins = 43

Let number of nickels = n

Let number of dimes = d

Let number of quarters = q

n+d+q=43 ...... (1)

Money in n nickels = n \times 0.05

Money in d dimes = d \times 0.10

Money in q quarters = q \times 0.25

Total money = $7.45

0.05n +0.10d+0.25q = 7.45\\\Rightarrow 5n +10d+25q = 745 .... (2)

The sum of the numbers of nickels and dimes is 3 less than the number of quarters.

i.e.

n+d=q-3

Let us put the value  in (1):

q-3+q=43\\\Rightarrow 2q= 43+3\\\Rightarrow q =23

Putting the value of q in (1) and (2):

n+d = 20 .... (3)

5n+10d+575 =745\\\Rightarrow 5n+10d =170\\\Rightarrow  n+2d =34 .... (4)

(4) - (3):

d = 14

Now, from (3):

n = 6

<em>Number of nickels = 6</em>

<em>Number of dimes = 14</em>

<em>Number of quarters = 23</em>

5 0
3 years ago
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