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Gennadij [26K]
3 years ago
8

If the first quadrant, you start at (6, 5) and move 3 units left

Mathematics
1 answer:
hjlf3 years ago
5 0

Left means that you are moving along the x axis. The coordinates are 6(x), and 5(y). You don't need to do anything to the y coordinates, because you are moving along the x axis. So all you have to do is imagine a number line. You are at 6, and you have to move 3 to the left, or the negative direction. You will be at 3,5.

Answer: 3,5

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Fy
rusak2 [61]

Answer:

From top to bottom;

1,1,3,3

Step-by-step explanation:

mathematically, for an even function;

f(x) = f(-x)

what this mean is that;

f(-1) = f(1)

f(-3) = f(3)

f(-5) = f(5)

f(-6) = f(6)

so we have it that;

f(-1) = 1

f(-3) = 1

f(-5) = 3

f(-7) = 3

7 0
2 years ago
Which point is located at (2,7)?
Anastasy [175]
Point S is located at 2,7.


8 0
3 years ago
Read 2 more answers
What are the answers for this page? #Geometry
mafiozo [28]

Answer:

For the first one:

D) The perpendicular bisector of line MN

For the second one:

You need a protractor (angle ruler) to measure the angle. After finding the measurement, divide it into two. After finding the result, find the point that has that angle.

Example -

The pie measures 120°.

120° ÷ 2 = 60°

Find the point that measures 60° and connect the points (from the start to the edge of the pie).

For the third one:

C) m∠ABD ≅ m∠CBD

4 0
3 years ago
Read 2 more answers
At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the firs
rewona [7]

Answer:

4032 different tickets are possible.

Step-by-step explanation:

Given : At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the first two races. If the first race runs 9 horses and the second runs 8.

To find : How many different tickets are possible ?

Solution :

In the first race there are 9 ways to pick the winner for first and second place.

Number of ways for first place - ^9C_1=9

Number of ways for second place - ^8C_1=8

In the second race there are 8 ways to pick the winner for first and second place.

Number of ways for first place - ^8C_1=8

Number of ways for second place - ^7C_1=7

Total number of different tickets are possible is

n=9\times 8\times 8\times 7

n=4032

Therefore, 4032 different tickets are possible.

8 0
3 years ago
Solve for x.<br> 6x + 5 = -x + 40<br> B. x= -5<br> A. x = -9<br> D. x= 9<br> C. x = 5
denis23 [38]
C, x=-5, hope this helps
3 0
3 years ago
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