Does anyone know if this is a function ?

Select the correct answer. Which pair of statements correctly compares the two data sets? A. The difference of the means is 1. T

Readme [11.4K]

Answer:

For this case since the p value is higher than the significance level we can FAIL to reject the null hypothesis and we can conclude that the true means are NOT significantly different at 10% of significance.

Step-by-step explanation:

Information provided

represent the mean for sample 1

represent the mean for sample 2

represent the sample standard deviation for 1

represent the sample standard deviation for 2

sample size for the group 2

Significance level provided

t would represent the statistic

Hypothesis to test

We want to verify if the true means for this case are significantly different, the system of hypothesis would be:

Null hypothesis:

Alternative hypothesis:

The statistic is given by:

(1)

And the degrees of freedom are given by

Replacing the info given we got:

The degreess of freedom are given by:

Now we can calculate the p value with the following probability:

For this case since the p value is higher than the significance level we can FAIL to reject the null hypothesis and we can conclude that the true means are NOT significantly different at 10% of significance.

Step-by-step explanation:

8 0

4 years ago

Read 2 more answers

Dylan keeps a fitness journal. Each week he runs 18 miles and swims 2 miles. What rules can you use to complete the table to sho

Kobotan [32]

Where are the boxes?

18/2 = 9

1st box - 18 : 2

2nd box - 36 : 4

3rd box - 72 : 8

etc . . .

6 0

3 years ago

At a student art fair, 100 projects were on display. Of all the

Daniel [21]

Answer: 90 projects in all 1/5 were photographs 1/5 of 90=90/5=18

Step-by-step explanation: done :)

8 0

3 years ago

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Select one of the factors of x3y2 8xy2 − 5x2 − 40. (xy2 5) (x2 4) (xy2 − 5) (x2 − 8) 4. select one of the factors of 5x2 7x 2. (

umka2103 [35]

The <em><u>correct answers</u></em> are:

(xy² − 5); none of the above; and (4x − 3)

Explanation:

To factor the first one, we will use factoring by grouping. First group the first two together and the second two together:

(x³y²+8xy²)+(-5x²-40)

Find the GCF of each group. The GCF of the first one is xy² and the GCF of the second is -5. Factor these out of each group:

xy²(x²+8)-5(x²+8)

We now have a GCF of the terms as we have rewritten them. Factoring out (x²+8), we have:

(x²+8)(xy²-5)

To factor the second question, we want factors of 10 that sum to 7. 5 and 2 work for this, so this is how we will split up the x term in our polynomial:

5x²+5x+2x+2

Group together the first two and the last two:

(5x²+5x)+(2x+2)

Find the GCF of each group. The first one has a GCF of 5x and the second has a GCF of 2. Factor these out:

5x(x+1)+2(x+1)

The GCF of the rewritten terms is (x+1). Factoring this out, we have

(x+1)(5x+2)

To factor the third question, we want factors of -24 that sum to 5. -3 and 8 will do this, and this is how we will split up the x term:

4x²+8x-3x-6

Group together the first two and the last two:

(4x²+8x)+(-3x-6)

Find the GCF of each group. The GCF of the first group is 4x and the GCF of the second group is -3. Factor these out:

4x(x+2)-3(x+2)

The GCF of the rewritten polynomial is (x+2). Factor this out:

(x+2)(4x-3)

4 0

3 years ago

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Thirty-seven percent of all Americans drink bottled water more than once a week (Natural resources Defense Council, December 4,

lesantik [10]

Answer:

a) The sampling distribution for n=540 has a mean sample proportion of p=0.37 and a standard deviation of σs=0.0208.

b) probability = 0.99998

d) probability = 0.99874

e) You gain 0.12% in probability for an increase of 80% in sample size.

The increase in sample size is not justified by the increase in probability, for this margin of error (Δp=0.09).

Step-by-step explanation:

a) We have a known population proportion π=0.37 and we have to describe the sampling distribution when the sample size is n=540.

The mean sample proportion is expected to be the same as the population proportion:

$\bar p = \pi = 0.37$

The standard deviation of the sampling will be the population standard deviation divided by the square root of the sample size:

$\sigma_s=\dfrac{\sigma}{\sqrt{n}}=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.37*0.63}{540}}=\sqrt{0.000431667}=0.0208$

Then, we can say that the sampling distribution will have a p=0.37 and a standard deviation σs=0.0208.

b) We have to calculate the probability that the sample proportion will be within 0.09 of the population proportion.

We can calculate the z-value as:

$z_1=\dfrac{p_1-\bar p}{\sigma_s}=\dfrac{0.09}{0.0208}=4.3269\\\\\\z_2=\dfrac{p_2-\bar p}{\sigma_s}=\dfrac{-0.09}{0.0208}=-4.3269$

As the distribution is symmetrical, we can calculate the probabilty that he sample proportion will be within 0.09 of the population proportion as:

$P(|p-\bar p|$

probability = 0.99998

d. Now the sample is smaller (n=300), so the standard deviation of the samping distribution:

$\sigma_s=\dfrac{\sigma}{\sqrt{n}}=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.37*0.63}{300}}=\sqrt{0.000777}=0.0279$

We have to recalculate the z-scores:

$z_1=\dfrac{p_1-\bar p}{\sigma_s}=\dfrac{0.09}{0.0279}=3.2258\\\\\\z_2=\dfrac{p_2-\bar p}{\sigma_s}=\dfrac{-0.09}{0.0279}=-3.2258$

And the probability is:

$P(|p-\bar p|$

probability = 0.99874

e. The increase in sample size is 80%

$\Delta n\%=\dfrac{n_1}{n_2}-1=\dfrac{540}{300}-1=1.8-1=0.8=80\%$

and the increase in probability is 0.12%

$\Delta P\%=\dfrac{P_1}{P_2}-1=\dfrac{0.99998}{0.99874}-1=1.0012-1=0.0012=0.12\%$

You gain 0.12% in probability for an increase of 80% in sample size.

The increase in sample size is not justified by the increase in probability, for this margin of error (Δp=0.09).

7 0

3 years ago