Mathew has $40.00, if Mathew wants to buy a bike for $70.00, how much more money will he need to buy the bike?

Please help with algebra class I’m struggling

adell [148]

Answer:

Step-by-step explanation:

For what mileages will company A (which has a flat rate of $111) be less than the cost for company B

Company A < Company B

111 < 75 + 0.80m

solving

111 - 75 < 75 - 75 + 0.80m

36 < 0.80m

36/0.80 < 0.80m/0.80

as we are dividing by a positive number, we don't have to change the direction of the < sign.

45 < m

or m > 45

so if Ali intends to drive more than 45 miles, Company A's vehicle will be less expensive to rent

5 0

2 years ago

Which choice describes a question that could be answered by moving the decimal point 3 places to the right? A. dividing 14.09 by

aliya0001 [1]

D. Multiplying 14.09 by 1,000.

8 0

3 years ago

Sam is selling homemade cookies to raise money for charity. Each cookie sells for $.50. Sam spent $90 on baking supplies and eac

Hunter-Best [27]

9514 1404 393

Answer:

360

Step-by-step explanation:

Sam obtains a "contribution margin" of $0.50 -0.25 = $0.25 per cookie. That will cover the cost of baking supplies when he sells ...

$90 / ($0.25/cookie) = 360 cookies

Sam needs to sell 360 cookies before he can start making a profit.

_____

If you like, you can find Sam's break-even point by equating revenue and cost. The is the number of cookies Sam must sell for a profit of 0, that is, for non-negative profit.

P = R - C

0 = R - C

R = C

0.50n = 90 +0.25n

0.25n = 90 . . . . subtract 0.25n

n = 90/0.25 = 360 . . . .divide by the coefficient of n

You may notice this is similar to our description above.

3 0

3 years ago

Please help me with this Statistics problem

Cerrena [4.2K]

It would be the first answer. Bubble. I don't know what you call it. But yeah, it's the first one.

7 0

3 years ago

Percentage grade averages were taken across all disciplines at a particular university, and the mean average was found to be 83.

Georgia [21]

Correct Ans:
Option A. 0.0100

Solution:
We are to find the probability that the class average for 10 selected classes is greater than 90. This involves the utilization of standard normal distribution.

First step will be to convert the given score into z score for given mean, standard deviation and sample size and then use that z score to find the said probability. So converting the value to z score:

$z-score= \frac{90-83.6}{ \frac{8.7}{ \sqrt{10} } } \\ \\ 
z-score =2.326$

So, 90 converted to z score for given data is 2.326. Now using the z-table we are to find the probability of z score to be greater than 2.326. The probability comes out to be 0.01.

Therefore, there is a 0.01 probability of the class average to be greater than 90 for the 10 classes.

5 0

3 years ago