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4 years ago

What is the direct linear variation equation for the relationship? Y varies directly with x and y = 12 when x = 3

Mathematics

1 answer:

RoseWind [281]4 years ago

8 0

Answer:ity

its 7

Step-by-step explanation:

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CAN SOMEONE HELP ME PLEASE ASAP!?

valentinak56 [21]

Answer:

last option

Step-by-step explanation:

b) 1/6 = 16.7 to 1dp

c) 45% = 45/100 = 9/20

d) 7/9 = 77.8% to 1dp

8 0

3 years ago

Given the following formula, solve for I.

azamat

answer: c. l =p-2b/2

step by step:

p=2(1-b)

p=2l-2b

p+2b/2=2l/2

l =p-2b/2

8 0

3 years ago

A 200-liter tank initially full of water develops a leak at the bottom. Given that 20% of the water leaks out in the first 5 min

Leya [2.2K]

Answer:

127.53 liters left after 10 minutes

Step-by-step explanation:

Let

$A \to Amount$

$t \to time$

Given

$A(0) = 200$ --- initial

$A(5) = 200 * (1 - 20\%) = 160$ --- the amount left, after 5 minutes

Required

$A(10)$ --- amount left after 5 minutes

To do this, we make use of:

$A(t) = A(0) * e^{kt}$

$A(5) = 160$ implies that:

$160 = 200 * e^{k*5}$

Divide both sides by 200

$0.80 = e^{k*5}$

Take natural logarithm of both sides

$\ln(0.80) = \ln(e^{k*5})$

$\ln(0.80) = \ln(e^{5k})$

$\ln(0.80) = 5k\ln(e)$

So, we have:

$-0.223 = 5k$

Divide by 5

$k = -0.045$

So, the function is:

$A(t) = A(0) * e^{kt}$

$A(t) = 200 * e^{-0.045t}$

The amount after 10 minutes is:

$A(10) = 200 * e^{-0.045*10}$

$A(10) = 200 * e^{-0.45}$

$A(10) = 127.53$

3 0

3 years ago

Solve for x. 5 = 2x - 3

Tasya [4]

Answer:

X=4

Step-by-step explanation:

3 0

3 years ago

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Use the graph of f(x) to find the solutions to the equation f(x) = 0.

stira [4]

The zeros would be -10 and 2. zeros are the numbers that touch the x-axis

7 0

4 years ago

Read 2 more answers