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3 years ago

What is the LCM of 20 and 15

Mathematics

1 answer:

ElenaW [278]3 years ago

5 0

Answer:

60Find the prime factors of the first number 20

2, 2, 5

Find the prime factors of the second number 15.

3, 5

Multiply all the highest exponent prime factors is the LCM value. Which is,

60

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A) 15 B) 25 C) 40 D) 60

Elodia [21]

Answer:

may be 25

idk the real but might be 25

Step-by-step explanation:

8 0

3 years ago

The mass of a grain of sand is approximately 2.8 × 10^−11 grams.

son4ous [18]

The answer is B hope this helps

4 0

3 years ago

Read 2 more answers

What is the value of n?

morpeh [17]

Answer:

n = 28 degree

Step-by-step explanation:

2n + 17 + 2n - 5 + 2n = 180 degree (sum of interior angles of a triangle)

6n +12 = 180

6n = 180 - 12

n = 168/6

n = 28 degree

6 0

3 years ago

Read 2 more answers

Add. Show Your Work.

PIT_PIT [208]

Hey there :)

$1 \frac{4}{5} + 1\frac{6}{10}$

Change mixed fraction into an improper fraction
$\frac{9}{5} + \frac{16}{10}$
$\frac{16}{10}$ : are both even numbers, so you can further simplify by dividing by 2
$\frac{16/2}{10/2} = \frac{8}{5}$

To add fractions, we need same denominator to proceed. Here we have no problem since both denominators are 5

$\frac{9}{5}+ \frac{8}{5} = \frac{9+8}{5}$
$\frac{17}{5}$

As a mixed fraction: $3 \frac{2}{5}$
______________________________________________________

$2 \frac{3}{4} - 1\frac{2}{8}$

Let us change the mixed fraction into an improper fraction:
$\frac{11}{4} - \frac{10}{8}$
$\frac{10}{8}$ : You can further simplify this since both are divisible by 2
$\frac{10/2}{8/2} = \frac{5}{4}$

We have the same denominator set for subtraction, so you do not have to find common denominators
$\frac{11}{4}- \frac{5}{4} = \frac{11-5}{4}$
$\frac{6}{4}$

As a mixed fraction: $1\frac{2}{4} = 1\frac{1}{2}$

6 0

3 years ago

N - 89 > 171. what inequality below true. 1. n=82. 2. n=105. 3. n=268. 4. n=300. 5. n=312

Maru [420]

Answer:

1. Assume the contrary, namely that √2 + √3 + √5 = r, where r is a rational number.

Square the equality √2 + √3 = r − √5 to obtain 5 + 2

√6 = r2 + 5 − 2r

√5. It follows

that 2√6 + 2r

√5 is itself rational. Squaring again, we find that 24 + 20r2 + 8r

√30

is rational, and hence √30 is rational, too. Pythagoras’ method for proving that √2 is

irrational can now be applied to show that this is not true. Write √30 = m

n in lowest

terms; then transform this into m2 = 30n2. It follows that m is divisible by 2 and because

2( m

2 )2 = 15n2 it follows that n is divisible by 2 as well. So the fraction was not in lowest

terms, a contradiction. We conclude that the initial assumption was false, and therefore

√2 + √3 + √5 is irrational.

Step-by-step explanation:

7 0

3 years ago