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irina1246 [14]
3 years ago
9

Jordan spent 22% of his time doing math homework. If hw spent 11 minutes on his math homework. How many minutes did he spend on

his homework
Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
8 0

Jordan spends 50 minutes on his homework.

Step-by-step explanation:

Given,

Time spent on Maths homework = 11 minutes

This represents the 22% time of his total homework.

Let,

x be the total time spent on homework.

22% of x = 11

\frac{22}{100}*x=11\\0.22x=11

Dividing both sides by 0.22

\frac{0.22x}{0.22}=\frac{11}{0.22}\\x=50

Jordan spends 50 minutes on his homework.

Keywords: percentage, division

Learn more about percentages at:

  • brainly.com/question/1542444
  • brainly.com/question/1548911

#LearnwithBrainly

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Find m∠DEC (the picture is not drawn to scale).
pochemuha

Answer:

M∠DEC equals 123º.

Step-by-step explanation:

The sum of a triangle's three angles always equal 180º. The exterior angle, x, equals the two non-adjacent interior angles.

180 - {(x - 45)+(x - 12)} = m∠DEC

m∠DEC + x = 180

<u>(x - 45) + (x - 12) = x</u>

Solving for x:

(x - 45) + (x - 12) = x

x - 45 + x - 12 = x                             Remove parenthesis

2x - 57 = x                                       Combine like terms

2x = x + 57                                      Add 57 to both sides

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Finding m∠D:

x - 45 = ?

<u>57 - 45 = </u><u>12º                                          </u>

Finding m∠C:

x - 12 = ?

<u>57 - 12 = </u><u>45º                                           </u>

<em>** </em><em>(Checking x: 12 + 45 = 57) </em><em>**</em>

<em>Finding </em>m∠DEC:

AC is a straight line, and because straight lines are equivalent to 180º, we subtract 57 from 180:

180 - 57 = 123º

Hope this helps,

❤<em>A.W.E.</em><u><em>S.W.A.N.</em></u>❤

8 0
3 years ago
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Tpy6a [65]

Answer:

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Step-by-step explanation:

Take paranthesis away.

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subtract 3.2 from 5.6

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Hope it helps1

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Answer:

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PEMDAS is our acronym for order of operations: Parentheses, exponents, multiplication, division, addition, subtraction.

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