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gogolik [260]
3 years ago
10

The monthly cost of driving a car depends on the number of miles driven. Lynn found that in May her driving cost was $380 for 48

0 mi and in June her cost was $450 for 830 mi. Assume that there is a linear relationship between the monthly cost C of driving a car and the distance x driven. Find a linear equation that relates C and d.
Mathematics
1 answer:
andrezito [222]3 years ago
7 0

Answer:

y=0.2x+284

Step-by-step explanation:

Let  x be the distance driven, d-distance and C our constant.

Our information can be presented as:

y=mx+c\\\\450=830x+C\ \ \ \ \ \ \ \ \ eqtn 1\\\\380=480x+C\ \ \ \ \ \ \ \ \ eqtn 2

#Subtracting equation 2 from 1:

70=350x\\x=0.2

Hence the fixed cost per mile driven,x is $0.20

To find the constant,C we substitute x in any of the equations:

450=830x+C\ \ \ \ \ \ \ X=0.2\\\therefore C=450-830\times0.2\\=284

Now, substituting our values in the linear equation:

y=0.2x+284       #y=cost of driving, x=distance driven

Hence the linear equation for the cost of driving is y+0.2x+284

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