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choli [55]
3 years ago
7

Simplify the expression below. (3-13)²+14/4²-5·2

Mathematics
1 answer:
Natalija [7]3 years ago
3 0
Calculate the difference, Reduce the fraction with 2, Multiply the numbers

(-10)^2+(7/2)^2-10


To raise a fraction to a power, raise the numerator and denominator to that power

100+49/4 -10

Calculate the sum

409/4

Or

102 1/4

Or

102.25

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HELP ASAP!!! WILL MARK BRAINLIEST!
Levart [38]

Answer:

outlier

Step-by-step explanation:

6 0
3 years ago
Two trains, Train A and Train B, simultaneously depart Station A and Station B. Station A and Station B are 252.5 miles apart fr
omeli [17]

-- The trains start moving at the same time.

-- The space between them is initially 252.5 miles.

-- They reduce the distance between them at the rate of (124.7+253.5)=378.2mph.

-- It will take them (252.5 / 378.2) = 0.6676 hour to meet.  

That's 40min 3.49sec .

-- After tooting and puffing toward each other for 8 minutes, they still have <em>32min 3.49sec</em> to go before they meet each other.  We're all hoping that they're on different tracks.  

4 0
3 years ago
(with steps please) Find the inverse Laplace transform, f(t), of the function: 16/(s-4)^3
Stells [14]

Answer:  The required inverse transform of the given function is

f(t)=8t^2e^{4t}.

Step-by-step explanation:  We are given to find the inverse Laplace transform, f(t), of the following function :

F(s)=\dfrac{16}{(s-4)^3}.

We have the following Laplace formula :

L\{t^ne^{at}\}=\dfrac{n!}{(s-a)^{n+1}}\\\\\\\Rightarrow L^{-1}\{\dfrac{1}{(s-a)^{n+1}}\}=\dfrac{t^ne^{at}}{n!}.

Therefore, we get

f(t)\\\\=L^{-1}\{\dfrac{16}{(s-4)^3}\}\\\\\\=16\times\dfrac{t^{3-1e^{4t}}}{(3-1)!}\\\\\\=\dfrac{16}{2}t^2e^{4t}\\\\\\=8t^2e^{4t}.

Thus, the required inverse transform of the given function is

f(t)=8t^2e^{4t}.

6 0
3 years ago
Can someone please read this?? I keep trying to but I get distracted! ​
Alex

Answer:

it translates to something i can't say on here ;)

5 0
3 years ago
Melissa works after school babysitting. she markes $18 an hour. write an equation that represents the relationship between the i
Fiesta28 [93]
Pay = $18 times the amount of hours she works
<span>p = 18h</span>
5 0
3 years ago
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