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3 years ago

Please answer ASAP Worth 20 points!!!

Mathematics

1 answer:

Fudgin [204]3 years ago

4 0

The x intercept is the 8 and the y is the -4

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Identify an equation in point-slope form for the line perpendicular to y = 1/4 x - 7 that passes through (-2,-6)

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I'm pretty sure it's y=4x-7. I could be wrong but the way I set it up is definitely close if not correct

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3 years ago

Eliminate the parameter t. Find a rectangular equation for the plane curve defined by the parametric equations.

djverab [1.8K]

Answer:

1. C

2. C

Step-by-step explanation:

1. x = $\sqrt{t}\\$ , y = 4t +3

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t = $x^{2}$

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y = 4( $x^{2}$ ) +3

y = 4 $x^{2}$ +3

2. x = 2t, y = t + 2

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t = x/2

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3 years ago

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4 years ago

Peter and Derrick are playing hockey, Peter bounces the puck against the wall to Derrick.

MArishka [77]

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Step-by-step explanation:

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3 years ago

HELPPPP!!!! Need the answer ASAP!!

Greeley [361]

Given that the functions $f(x)=x+4$ and $g(x)=x^{3}$

We need to determine the value of the function $(g \ {\circ} f)(-3)$

First, we shall determine the composition of the function $(g \circ f)(x)$

Function $(g \circ f)(x)$ :

Let us determine the function $(g \circ f)(x)$

Thus, we have;

$(g \circ f)(x)=g[f(x)]$

$=g[x+4]$

$=(x+4)^3$

$(g \circ f)(x)=x^3+3x^2(4)+3x(4)^2+(4)^3$

$(g \circ f)(x)=x^3+12x^2+48x+64$

Thus, the function is $(g \circ f)(x)=x^3+12x^2+48x+64$

Value of the function $(g \ {\circ} f)(-3)$ :

The value of the function can be determined by substituting x = -3 in the function $(g \circ f)(x)=x^3+12x^2+48x+64$

Thus, we have;

$(g \circ f)(-3)=(-3)^3+12(-3)^2+48(-3)+64$

Simplifying the terms, we get;

$(g \circ f)(-3)=-27+12(9)+48(-3)+64$

$(g \circ f)(-3)=-27+108-144+64$

$(g \circ f)(-3)=1$

Thus, the value of the function $(g \ {\circ} f)(-3)$ is 1.

8 0

3 years ago