The object with dimensions and with mass 250.6 g will have a density equal to
.
<u>Given:</u>
Dimensions of the object =
length = l = 5.54 cm
width = w = 10.6 cm
height = h = 199 cm
Mass of the object = m = 250.6 g
<u>Formula:</u>
The relation between density, mass and volume of any object is given by:
Since volume of an object with length (l), width (w) and height (h) [assuming a rectangular object] can be defined as,
Density of the object is
The outdoor temperature, also known as the ambient temperature, is a measure of the amount of heat in the environment and this depends on the kind of environment.
<h3>Temperature</h3>The outdoor temperature around here is about 33 .
The temperature in the tropical area, where this area belongs, varies between 27 to 35 with an annual average of about 28
.
In order words, tropical regions are generally warm, unlike temperate regions.
Tropical regions also have two distinct seasons, the rainy and the dry seasons. This is unlike temperate regions that have summer, spring, winter, and autumn.
More on temperature can be found here: brainly.com/question/15267055
Answer:
0.7atm
Explanation:
Given parameters:
Initial temperature = 25.2°C in Kelvin; 25.2 + 273 = 298.2K
Initial pressure = 0.6atm
Final temperature = 72.4°C in kelvin = 72.4 + 273 = 345.4K
Unknown:
Final pressure = ?
Solution:
Since we are dealing with pressure temperature relationships under a fixed volume, we use a simplification of the combined gas law to solve this problem.
At fixed volume;
where P and T are temperature values
1 and 2 are the initial and final states
Input the parameters and solve for P₂
P₂ = 0.7atm