Answer:
The Emf of the given cell at [Fe2+] = 2.0 M and [Fe3+] = 1.9 M is 0.48 V
Explanation:
The half cell reaction can be written as :
Anode-Half (oxidation) :
......E = 0.77 V
(multiply this equation by 4 to balance the electrons)
Cathode-half (reduction)
....E= 1.23 V



According to Nernst Equation


n = number of electron transferred in the cell reaction = 4
The balanced equation is :


![log Q = \frac{[Fe^{3+}]^{4}}{[Fe^{2+}]^{4}}](https://tex.z-dn.net/?f=log%20Q%20%3D%20%5Cfrac%7B%5BFe%5E%7B3%2B%7D%5D%5E%7B4%7D%7D%7B%5BFe%5E%7B2%2B%7D%5D%5E%7B4%7D%7D)
![log Q = \left ( \frac{[Fe^{3+}]}{[Fe^{2+}]} \right )^{4}](https://tex.z-dn.net/?f=log%20Q%20%3D%20%5Cleft%20%28%20%5Cfrac%7B%5BFe%5E%7B3%2B%7D%5D%7D%7B%5BFe%5E%7B2%2B%7D%5D%7D%20%5Cright%20%29%5E%7B4%7D)

Insert the value of log Q in Nernst Equation:

(using :
)


People would rush to the store to buy supplies and there might not be enough for the "last minute noticed" people
Answer:
I don't think so
Explanation:
The equation doesn't look balanced
Answer: 1.Sulfuric acid is a catalyst
2. Vanadium(v) oxide is a catalyst