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3 years ago

What is the perimeter of △ABC? Round each step to the nearest tenth.

Mathematics

1 answer:

trapecia [35]3 years ago

5 0

Required Perimeter = AB + BC + CA
AB = sqrt((5 - (-1))^2 + (-1 - 1)^2) = sqrt(6^2 + (-2)^2) = sqrt(36 + 4) = sqrt(40) = 6.3
BC = sqrt((-1 - 0)^2 + (1 - (-3))^2) = sqrt((-1)^2 + 4^2) = sqrt(1 + 16) = sqrt(17) = 4.1
CA = sqrt((0 - 5)^2 + (-3 - (-1))^2) = sqrt((-5)^2 + (-2)^2) = sqrt(25 + 4) = sqrt(29) = 5.4

Perimeter = 6.3 + 4.1 + 5.4 = 15.8 units

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In this problem we have:

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We notice that the difference between the distance travelled on the (n+1)-th day and the distance travelled on the n-th day doubles every day. In fact:

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Which can be rewritten using the general formula:

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This means that

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By applying this formula recursively, we can find the 7th term, which is the distance travelled on the 7th day:

$d_1=1\\d_2=1.3\\d_3=1.9\\d_4=3.1\\d_5=3.1+2\cdot 1.2=5.5\\d_6=5.5+2\cdot 2.4=10.3\\d_7=10.3+2\cdot 4.8=19.9 mi$

So, the distance travelled on the 7th day is 19.9 miles.

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