What is the perimeter of △ABC? Round each step to the nearest tenth.

Mathematics

1 answer:

trapecia [35]3 years ago

5 0

Required Perimeter = AB + BC + CA
AB = sqrt((5 - (-1))^2 + (-1 - 1)^2) = sqrt(6^2 + (-2)^2) = sqrt(36 + 4) = sqrt(40) = 6.3
BC = sqrt((-1 - 0)^2 + (1 - (-3))^2) = sqrt((-1)^2 + 4^2) = sqrt(1 + 16) = sqrt(17) = 4.1
CA = sqrt((0 - 5)^2 + (-3 - (-1))^2) = sqrt((-5)^2 + (-2)^2) = sqrt(25 + 4) = sqrt(29) = 5.4

Perimeter = 6.3 + 4.1 + 5.4 = 15.8 units

You might be interested in

A triangular pyramid with a height of 9 inches has a volume of 63 cubic inches. If the height of the triangular base is 6 inches

Bond [772]

Option D: 21 in is the base length of the triangular base.

Explanation:

Given that a triangular pyramid with a height of 9 inches has a volume of 63 cubic inches.

The height of the triangular base is 6 inches.

We need to determine the base length of the triangular pyramid.

The base length of the triangular pyramid can be determined using the formula,

$Volume =\frac{1}{3} \times Bh$

Substituting $Volume=63$ and $Height=9$ in the above formula, we get,

$63 =\frac{1}{3} \times B(9)$

Simplifying the terms, we get,

$63 =3B$

Dividing both sides by 3, we have,

$21=B$

Thus, the base length of the triangular pyramid is 21 in

Hence, Option D is the correct answer.

3 0

3 years ago

How many quarts of soil are used to fill 2 flower pots? Each pot holds 3 2/5

kirill [66]

I’m 2 stuck on the same answer

5 0

3 years ago

Read 2 more answers

Solving quadratic equation using the completing method.<br>(a).x^2+6x+1=0

irina1246 [14]

Answer:

$x = -3 + 2\sqrt2 \ , \ x = -3 - 2\sqrt2$

Step-by-step explanation:

x² + 6x + 1 = 0

a = 1 , b = 6 , c = 1

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\\\\x = \frac{-6 \pm \sqrt{36-4}}{2}\\\\x=\frac{-6 \pm \sqrt{32}}{2}\\\\x= \frac{-6 \pm \sqrt{16 \times 2}}{2}\\\\x = \frac{-6 +4\sqrt2 }{2}\\\\x = -3 + 2\sqrt2 \ , \ x = -3 - 2\sqrt2$