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alisha [4.7K]
1 year ago
13

Evaluate P + Q if possible.

Mathematics
2 answers:
jenyasd209 [6]1 year ago
4 0

Since the matrices have different dimensions, it is not possible to calculate the expression...

  • <em>T</em><em>h</em><em>u</em><em>s</em><em>,</em><em> </em><em>O</em><em>p</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>C</em><em> </em><em>i</em><em>s</em><em> </em><em>c</em><em>o</em><em>r</em><em>r</em><em>e</em><em>c</em><em>t</em><em>!</em><em>!</em><em>~</em>
Sunny_sXe [5.5K]1 year ago
3 0

Here we are given with <em>two matrices</em> as follows

  • {\bf{P=\begin{bmatrix}5& 0& 1 \\ 2& 8& 5\end{bmatrix}}}

And

  • {\bf{Q=\begin{bmatrix}6& 5& 0 \\ 1& 2& 8 \\ 5& 4& 1 \end{bmatrix}}}

We need to find<em> P+Q </em>. But , <em>matrix addition</em> is only possible iff the order of all <em>matrices</em> which are <em>being added</em> is <em>same</em> . Now , here order of <em>P</em> is <em>2 × 3</em> while that of <em>Q</em> is <em>3 × 3 </em>. So , <em>matrix</em> <em>addition</em> isn't <em>possible.</em>

<em>Hence , Option C) Not possible is correct</em>

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Before we can calculate the total distance, we will need to get the hypotenuse on  both sides using the Pythagoras theorem as shown:

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