The difference of two squares factoring pattern states that a difference of two squares can be factored as follows:
So, whenever you recognize the two terms of a subtraction to be two squares, you can factor it as the sum of the roots multiplied by the difference of the roots.
In this case, the squares are obvious: 
is the square of 
, and 
is the square of 
So, we can factor the expression as
![(x+2)^2 - (y+2)^2 = [(x+2)+(y+2)] - [(x+2)+(y+2)]](https://tex.z-dn.net/?f=%20%28x%2B2%29%5E2%20-%20%28y%2B2%29%5E2%20%3D%20%5B%28x%2B2%29%2B%28y%2B2%29%5D%20-%20%5B%28x%2B2%29%2B%28y%2B2%29%5D%20)
(the round parenthesis aren't necessary, I used them only to make clear the two terms)
We can simplify the expression summing like terms:
![(x+2)^2 - (y+2)^2 = [(x+2)+(y+2)][(x+2)-(y+2)] = (x+y+4)(x-y)](https://tex.z-dn.net/?f=%28x%2B2%29%5E2%20-%20%28y%2B2%29%5E2%20%3D%20%5B%28x%2B2%29%2B%28y%2B2%29%5D%5B%28x%2B2%29-%28y%2B2%29%5D%20%3D%20%28x%2By%2B4%29%28x-y%29%20)
When exponents are separated by a parenthesis it means you need to add them. Because the parenthesis is around the entire number then you raise everything inside the parenthesis to the outside exponent. Then anything raised by 0 as an exponent is automatically 1.
You think of this visually as 3a*3a*3a= 27a^9 is your answer
Answer:The function v(x) has the largest value when x = 4.
Solution:
x=4;
e(4) = 4^2 + 6×4 + 21=16+24+21=61
m(4) = 8×4=32
v(4) = 31×4=124
v(4)>e(4)>m(4)
Therefore,The function v(x) has the largest value when x = 4.
Answer:
Step-by-step explanation:
A(4;1) B(1;3)
●use distance formula (see photo^)
Answer:
can you make the picture bigger and show the all of the answers, if yes i believe i can do the problem thank you
Step-by-step explanation:
