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Lapatulllka [165]
3 years ago
12

How do I do this?need help​

Mathematics
1 answer:
Lelu [443]3 years ago
8 0
I have no clue at all
You might be interested in
Factor 20a + 45.............................................
Delvig [45]

Answer:5(4a+9)

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
-3x^{2}-21x-54 what are the zeros? (Solutions)
Irina-Kira [14]
The only way to solve if it is equal to something
assuming that the teacher wanted you to make it equal to zero do
0=-3x^2-21x-54

remember if we can do
xy=0 then assume x and y=0

so factor

0=-3x^2-21x-54
undistribute the -3
0=-3(x^2+7x+18)
remember 0 times anything=0 so
x^2+7x+18 must equal zero
use quadratice formula which is

if you have
ax^2+bx+c=0 then
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}

x^2+7x+18
a=1
b=7
c=18

x=\frac{-7+/- \sqrt{7^{2}-4(1)(18)} }{2(1)}
x=\frac{-7+/- \sqrt{49-72} }{2}
x=\frac{-7+/- \sqrt{-23} }{2}
i=√-1
x=\frac{-7+/- i\sqrt{23} }{2}



the zerose would be
x=\frac{-7+ i\sqrt{23} }{2} or \frac{-7- i\sqrt{23} }{2}




4 0
3 years ago
Can you help me with this ,please?​
lana [24]
First one and the last one are rational. And the other two of them are irrational.
8 0
3 years ago
What is the value of x in trapezoid ABCD?<br>x=15<br>x=20<br>x=45<br>x=60<br>​
Zepler [3.9K]

Answer:

I think its x=15

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Points S,U, and T are the midpoints of the sides of PQR. Which statements are correct ? 1/2QP=UT 1/2TS=RQ SU=PR SU||RP UT=RP
cricket20 [7]

Answer:

\frac{1}{2} QP = UT

Step-by-step explanation:

GIVEN : In ΔPQR

              S is the mid point of QP

              U is the mid point of PR

              T is the mid point of  QR

Solution :

i) is true i.e \frac{1}{2} QP = UT

Refer the attached file

By mid segment theorem i.e. In a triangle, the line joining the midpoints of any two sides will be parallel to the third side and that same line joining the midpoints is also half of length of third side .

UT is the line joining the two mid points . So, by theorem given above UT is parallel to PQ and  1/2QP=UT.

So, (i) statement is true i.e. \frac{1}{2} QP = UT

6 0
3 years ago
Read 2 more answers
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