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Ann [662]
3 years ago
7

This is the answer to a problem or an equation. Example: For 3x+6=27, this is x=7

Mathematics
1 answer:
Finger [1]3 years ago
8 0

Answer:

x=7 is the answer

3x+6=27 is the equation

x=7 is the correct answer for the equation.

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Susanne checks the temperature at 10:00 p.m. she notices that, if the temperature falls by 3 more degrees, it will break the rec
goldfiish [28.3K]

Answer:

Susanne checks the temperature at 10:00 p.m. she notices that, if the temperature falls by 3 more degrees, it will break the record low temperature for that day, which is 26 degrees.

Step-by-step explanation:

3 0
3 years ago
TIME CRUCIAL!! i will give you thanks please help!!! ASAP! will mark as brainliest!!
ozzi
\overline{y} (prounounced "y bar") is the mean of the y values

Add up the y values to get
5+7+10+15+18 = 55

Then divide by 5 (because there are five y values) to get
55/5 = 11

Therefore,
\overline{y} = 11

The answer is choice C
3 0
3 years ago
The edge of the square is 33 cm.
Aleks [24]

Answer:

46.6

Step-by-step explanation:

{x}^{2}  =  {33}^{2}  +  {33}^{2}  \\ x =  \sqrt{2178}  \\ x = 46.6 \: cm

4 0
2 years ago
During halftime of a basketball ​game, a sling shot launches​ T-shirts at the crowd. A​ T-shirt is launched from a height of 4 f
Sonbull [250]

Answer:

(a) The time the T-shirt takes to maximum height is 2 seconds

(b) The maximum height is 68 ft

(c) The range of the function that models the height of the T-shirt over time given above is 4 + 64\cdot t - 16 \cdot  t^{2}

Step-by-step explanation:

Here, we note that the general equation representing the height of the T-shirt as a function of time is

h = h_1 + u\cdot t - \frac{1}{2} \cdot g  \cdot  t^{2}

Where:

h = Height reached by T-shirt

t = Time of flight

u = Initial velocity = 64 ft/s

g = Acceleration due to gravity (negative because upward against gravity) = 32 ft/s²

h₁ = Initial height of T-shirt = 4 ft

(a) The maximum height can be found from the time to maximum height given as

v = u - gt

Where:

u = Initial velocity = 64 ft/s

v = Final upward velocity at maximum height = 0 m/s

g = 32 ft/s²

Therefore,

0 = 64 - 32·t

32·t = 64 and

t = 64/32 = 2 seconds

(b) Therefore, maximum height is then

h = 4 + 64\times 2 - \frac{1}{2} \times 32  \times  2^{2}

∴ h = 68 ft

The T-shirt is then caught 41 ft above the court on its way down

(c) The range of the function that models the height of the T-shirt over time given above is derived as

h = h_1 + u\cdot t - \frac{1}{2} \cdot g  \cdot  t^{2}

With u = 64 ft/s

g = 32 ft/s² and

h₁ = 4 ft

The equation becomes

h =4 + 64\cdot t - \frac{1}{2} \times 32  \cdot  t^{2} = 4 + 64\cdot t - 16 \cdot  t^{2}.

6 0
3 years ago
Sarah and Jake timed themselves while running. Who ran at a faster speed?
RUDIKE [14]

Answer:

Jake

Step-by-step explanation: 176 Divided by 4 divided bye divided = 44, so Jake ran only 44 minutes therefore Sarah ran more.

4 0
4 years ago
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