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11111nata11111 [884]
4 years ago
10

What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the point (2,5

)?​

Mathematics
1 answer:
KonstantinChe [14]4 years ago
6 0

Answer:

C

Step-by-step explanation:

The point slope form of a line is y - y_1 = m(x-x_1). If the point is (2,5) then the equation will be y - 5=m(x-2). Only option C matches this equation.

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Graph the function f(x) = -42-4+ 5 on the axes below. You must plot the
valentina_108 [34]

Answer:

- attached graph

- Horizontal Asymptote: y = 5

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Step-by-step explanation:

- Exponential functions have a horizontal asymptote. The equation of the horizontal asymptote

y = -4^(x-4) + 5

  = -4^(4-4) + 5

  = -4^(0) + 5

  = -1 + 5

  = 4

y = -4^(x-4) + 5

  = -4^(5-4) + 5

  = -4^(1) + 5

  = -4 + 5

  = 1

7 0
2 years ago
I'm not sure how to solve please help
wel
Follow these step:
So you want to start with adding the 5 to the other side of the equation so it would become 8=g/4
Then you want to multiply each side by 4 so it becomes 32=g

The answer is g=34
I hope this helps :)
8 0
3 years ago
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3x-1/2(8x-2)=4
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Y = 5

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