Question

Prove that the diagonals of a parallelogram bisect each other.

Answer 1

Answer:

2

Step-by-step explanation:

Well by definition a Rhombus is an equilateral paralelogram, AB =BC=CD=DA with all congruent sides, and Diagonals with different sizes.

Also a midpoint is the mean of coordinates, like E is the mean coordinate of A,C, and B, D

$\frac{B+D}{2}=E\\ \\ B+D=2E\\ and\\\\ \frac{A+C}{2} =E\\ A+C=2E$

So the sum of the Coordinates B and D over two returns the midpoint.

And subsequently the sum of the Coordinates B +D equals twice the E coordinates. The same for the sum: A +C

Given to the fact that both halves of those diagonals coincide on E despite those diagonals have different sizes make us conclude, both bisect each other.

Answer 2

Answer:

2

Step-by-step explanation:

The diagonals of a parallelogram bisect each other. Since midpoints will be involved, use multiples of 2 to name the coordinates for B, C, and D.