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fenix001 [56]
3 years ago
13

How to write an equation of the line through the point (-2,1) that is perpendicular to the line 5x+9y=-9

Mathematics
1 answer:
Julli [10]3 years ago
6 0

Answer:

\large\boxed{y=\dfrac{5}{9}x+\dfrac{19}{9}}

Step-by-step explanation:

\text{Let}\\\\k:y=m_1x+b_1\\\\l:y=m_2x+b_2\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\\\l\ \parallel\ k\iff m_1=m_2\\\\===================================\\\\\text{We have the equation i the standard form.}\\\text{ Convert it to the slope-intercept form}\ y=mx+b:\\\\5x+9y=-9\qquad\text{subtract}\ 5x\ \text{from both sides}\\\\9y=-5x-9\qquad\text{divide both sides by 9}\\\\y=-\dfrac{5}{9}x-1\to m_1=-\dfrac{5}{9}\\\\m_2=-\dfrac{1}{m_1}\to m_2=-\dfrac{1}{-\frac{5}{9}}=\dfrac{9}{5}

\text{We have the equation:}\\\\y=\dfrac{5}{9}x+b\\\\\text{Put the coordinates of the point (-2, 1) to the equation:}\\\\1=\dfrac{5}{9}(-2)+b\\\\1=-\dfrac{10}{9}+b\qquad\text{add}\ \dfrac{10}{5}\ \text{to both sides}\\\\\dfrac{19}{9}=b\to b=\dfrac{19}{9}

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If I have a <img src="https://tex.z-dn.net/?f=4%20%5Ctimes%204" id="TexFormula1" title="4 \times 4" alt="4 \times 4" align="absm
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Answer:

576 ways

Step-by-step explanation:

There are 4 choices for the column of pawn in the 1st row

There are 3 choices for the column of pawn in the 2nd row,

There are 2 choices for the column of pawn in the 3rd row, and

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Which gives a total of 4! = 24

Also, the pawns are distinct, so there are 4! ways to place them in these chosen positions;

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3 years ago
Write the equation in slope-intercept form of the line that includes the point (3,2) and has a slope of 4/3.
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Answer:

y = \frac{4}{3}x - 2

Step-by-step explanation:

Given:

Slope (m) = ⁴/3

Point on the line = (x, y) = (3, 2)

Required:

Write the equation in slope-intercept form which is y = mx + b

Solution:

Since we know the slope(m), we need to find the y-intercept (b).

This, substitute (x, y) = (3, 2) and m = ⁴/3 into y = mx + b, and solve for b. Thus:

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